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2 years ago

HEY hey hellooo HELP ME!!

Mathematics

2 answers:

Bezzdna [24]2 years ago

6 0

Answer:

1, 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61, 66, 71.

nekit [7.7K]2 years ago

4 0

Answer:

1, 6, 11, 16, 21, 26, 31, 36, 41 ,46 ,51, 56, 61,66, 71, 76, 81, 86

Step-by-step explanation:

5 is added to each number

It also follows a pattern of 1 then 6 at the end of each repeated number from 1 -10

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Arithmetic Sequences:

lisov135 [29]

Início = 6 h
9 x 6 = 54
6:54 passou o nono ônibus
próximo ônibus = 6:54 + 9 = 7:03
próximo = 7:03 + 9 = 7:12
próximo = 7:12 + 9 = 7:21
você chegou às 7:16 e vai esperar 21-16 = 5 minutos

3 0

2 years ago

I need help with my little brothers homework?

erik [133]

I only did the first part but maybe later I will solve the rest too. If there are any errors but tell me so I can update the pic.

7 0

3 years ago

Read 2 more answers

Use interval notation to express the following:<br> The set of all numbers less than 2.

AlexFokin [52]

Answer:

( - infinity, -3 ] [ -2, infinity )

square bracket means it includes the end point.

Step-by-step explanation:

(-∞, -3]U [-2,∞)

3 0

3 years ago

What is the order of this from least to greatest. 4.37, 5.844, 5 21/25,117/20

vesna_86 [32]

21/25, 4.37, 5, 5.844, 117/20

6 0

2 years ago

What is ∛1728. Then multiplied by ∛14903

NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate $\sqrt[3]{1728}$ and then multiply the result by $\sqrt[3]{14903}$

Let us first evaluate $\sqrt[3]{1728}$

$\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12$

As need to multiply 12 by $\sqrt[3]{14903}$

$\Rightarrow 12 \times \sqrt[3]{14903}$

On solving $\sqrt[3]{14903}$ , we get

$\sqrt[3]{14903}=24.608$

$\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306$

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0

2 years ago