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SSSSS [86.1K]
3 years ago
14

Which point on the number line indicates a number that is less than 9.1 and greater than 6.5

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:


Step-by-step explanation:


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PLEASE HELP ASAP
pishuonlain [190]
You have that:

 1. By definition, a binomial is a polynomial formed by two terms. 
 2. A quintic binomial is a binomial of degree 5. This means that its highest exponent is 5.
 3. Keeping this on mind, you must identify which binomial has degree 5.
 4. As you can see, the expression <span>3x^5+2 is a binomial, because it has two terms and the highest degree is 5.
 5. Thefore, the answer is: </span>3x^5+2
8 0
3 years ago
√44 is between what 2 numbers?<br><br> A.4 and 5<br> B.5 and 6<br> C.6 and 7<br> D.7 and 8
Gemiola [76]
I believe the answer is C.

6 0
3 years ago
Find the area of the figure
lana [24]

Answer:

Below

Step-by-step explanation:

First I found the area of the portion that extends off (if that makes sense??)

It is a triangle, so use A = bh/2

A = (2)(6) / 2

   = 6 cm^2

Next I found the area of the rectangle using A = LW

A = (6)(3)

   = 18 cm^2

Total area = 18 + 6

                 = 24 cm^2

Hope this helps! Best of luck <3

5 0
3 years ago
Read 2 more answers
Rearrange the formula V = 1 3 πr2h for h. A) h = 3V πr2 B) h = V 3πr2 C) h = 3πr2 V D) h = πr2 3V
stiks02 [169]

Answer:

Option a) h=\frac{3V}{\pi r^{2} }

Step-by-step explanation:

The given formula seems to represent the volume of right circular cone. The correct formula is:

V=\frac{1}{3} \pi r^{2} h

We have to rearrange the formula for h. This means we have to move h on one side of the formula and all the other variables and constants on the other side of the equation. This can be done as shown below:

V=\frac{1}{3} \pi r^{2} h\\\\3V=\pi r^{2} h\\\\h=\frac{3V}{\pi r^{2} }

5 0
3 years ago
Find a 95% confidence interval for the difference in proportions, pt-po, two ways, using StatKey or other technology and percent
beks73 [17]
A bit confusing for me to be able to answer this for you… any way you can simplify your question?
4 0
2 years ago
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