Let,
Length = a
Width= b
a-b=4 --eq(1)
since perimeter of parallelogram P=2(a+b)
therefore
2a+2b=72 --eq(2)
eq(1)=>
a=b+4
substitute the value of a in eq 2
Eq(2)=>
2(b+4)+2b=72
2b+8+2b=72
4b=72-8
4b=64
b=16
Substitue the value of b in eq(1)
Eq(1)=>
a-16=4
a=20
Answer:
104°
Step-by-step explanation:
If segments NO and NM are congruent, then angles NMO and NOM are congruent. So, their supplements, angles NML and NOP are congruent. That is ...
∠NML ≅ ∠NOP = 104°
∠NML = 104°
1. first option= 84
2. first option= (1+6)/7
3. last option= 0.40-m