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Nezavi [6.7K]
3 years ago
15

P - 3 1/6 = -2 1/2 what is p?

Mathematics
2 answers:
sammy [17]3 years ago
8 0
P-1/2=-1

P=-1+1/2

P=-2+1/2
P=-1/2
P=-0.5
goldfiish [28.3K]3 years ago
7 0
<span>P - 3 1/6 = -2 1/2

3 1/6- 21/2 

p=2/3 </span>
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If you rent an apartment, which home insurance coverage do you not need?
Reika [66]
I think that it should be a because you don't have real property
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What would x equal for these two?<br> 15/24 = x/3 &amp; 7/24 = 3/x<br><br> Thank you!!!
vesna_86 [32]

The first one you have \frac{15}{24}=\frac{x}{3} . To solve this you would multiply both sides by 3.

\frac{45}{24}=x

Then simplify by dividing the numerator and denominator by 3.

\frac{15}{8}=x (or in a mixed fraction 1\frac{7}{8})

The second one you have \frac{7}{24}=\frac{3}{x} . To solve this you would multiply both sides by x.

\frac{7}{24}x=3

Now you would divide both sides by \frac{7}{24}.

x=\frac{3}{\frac{7}{24}}

You now then multiply 3 by 24 and then divide by 7.

\frac{72}{7}

x=\frac{72}{7} (in a mixed fraction would be 10\frac{2}{7})

6 0
3 years ago
Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution
Blababa [14]

Answer:

If you mean only one rational solution, the answer is

k_1 = 8, k_2 = -8

If you mean at least 1 rational solution, the answer is

k\in (-\infty, -8]\cup[8, \infty)

Step-by-step explanation:

4x^2 + kx + 4 = 0

Let's calculate the discriminant.

\Delta = b^2 - 4ac

\Delta = k^2 -4 \cdot 4 \cdot 4

\Delta = k^2 -64

Now, remember that:

\text{If } \Delta > 0 : \text{2 Real solutions}

\text{If } \Delta = 0 : \text{1 Real solution}

\text{If } \Delta < 0 : \text{No Real solution}

Therefore, I will just consider the first two cases.

k^2 - 64 > 0

and

k^2 -64 = 0

\boxed{\text{For } k^2 - 64 > 0}

k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64}   \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)

\boxed{\text{For } k^2 - 64 = 0}

k^2 = 64 \Longleftrightarrow k=\pm\sqrt{64} \implies k_1 = 8, k_2 = -8

7 0
3 years ago
List the set of all even numbers between 2 and 10, inclusive.
Molodets [167]
The answer would be 2,4,6,8,10

5 0
3 years ago
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A metal plate, with constant density 5 g/cm^2, has a shape bounded by the curbe y = x^2 and the x-axis, with 0&lt;= x &lt;= 3 an
nignag [31]

Answer:

a) 45 g

b) greater (make the graph youself on desmos or something)

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area = integral 0 to 3 of x^2 dx = [1/3x^3] 0 to 3 = 9

mass = density * area = 5 * 9 = 45 grams

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x = integral 0 to 3 of 5x^3 dx / mass = (405/4) / 45 = 9/4

4 0
4 years ago
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