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polet [3.4K]
3 years ago
12

What is the scale of a drawing where a 36 foot tall statue is 9 inches tall?

Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

Your answer will be C.

Step-by-step explanation:

Please correct me if I'm wrong! :)

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How to solve quadratic equation with brackets<br>​
shtirl [24]

Answer:

Solving Quadratic Equations

  1. Put all terms on one side of the equal sign, leaving zero on the other side.
  2. Factor.
  3. Set each factor equal to zero.
  4. Solve each of these equations.
  5. Check by inserting your answer in the original equation.
6 0
3 years ago
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A pair of sneakers costs 400 Rand on a 25% discount sale? What was the original price of the sneakers before the discount.
Mnenie [13.5K]

Answer:

1600

Step-by-step explanation:

Do 400 ÷ 0.25 = 1600

0.25 because of the discount

Check by doing 1600 X 0.25 and it should be 400 which it is

4 0
3 years ago
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Select two answer choioces
dexar [7]

Answer:

C or 3rd option

Step-by-step explanation:

1/3 - 2/5

15/15 - 6/15

9/15

B is not correct

2/5 - 1/3

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6 0
3 years ago
Can you help? Having a hard time figuring this out. Thanks
Dmitrij [34]

Answer:

3a) The value of  x = 56

3b) The measure of ∠ H T M = 90°

3c) The radius of the circle = 53

Step-by-step explanation:

3a) ∵ A F is a tangent to the circle O at point F

∵ Secant AH intersects circle O at point T

∴ (A F)² = (A T)(A H)

∴ 7( x + 7) = (21)² ⇒ ÷ 7

∴ x + 7 = 63

∴ x = 63 - 7 = 56

3b) ∵ HM is a diameter

∴ The measure of the arc HM = 180° ⇒ semi-circle

∵ ∠ H T M is inscribed angle subtended by the arc HM

∴ m ∠ H T M = half the measure of arc HM

∴ m ∠ H T M = 180° ÷ 2 = 90°

3c) ∵ Δ H T M is a right angle triangle at T

∴ (H M)² = (M T)² + (H T)² ⇒ Pythagorean theorem

∴ (H M)² = (90)² + (56)²

∴ (H M)² = 11236

∴ HM = \sqrt{11236} = 106

∴ OM = 106 ÷ 2 = 53

∵ OM is the radius of the circle O

∴ The radius  = 53

4 0
3 years ago
(x+40):12+78-88 exercitiul se face prin metoda mersului invers ajuor!
Mashutka [201]
What?
i dont know maybe...hmmmm
6 0
3 years ago
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