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Annette [7]
3 years ago
11

Show how 4×3/4 can be solved using multiplication and division.

Mathematics
1 answer:
PIT_PIT [208]3 years ago
3 0
All you have to do is times 4 by both the numerator and denominator therefore the answer is 12/16
Or in its simplest form 3/4
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Which of the following solutions to the inequality -7x+14>-3x -6? Select all that apply
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3 0
2 years ago
In the lab, Alonzo has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solut
ioda

Answer:

200 mL

Step-by-step explanation:

If x is the volume of solution B:

0.06 (500) + 0.20 x = 0.10 (500 + x)

30 + 0.20 x = 50 + 0.10 x

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4 0
3 years ago
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Please help me, this is my last question and I’ve been trying all day
aalyn [17]

Answer:

sqrt(x-3)+3

Step-by-step explanation:

Consider the graph of a function f(x), if we want to move the graph right by a units we have f(x-a), to then move it up by b units we have f(x-a)+b. In this case you replace the x with x-a to get sqrt(x-a)+b

Notice how the graph goes through (3,3) and (4,4) like the original graph goes through (0,0) and (1,1). This means we want to translate it 3 up and 3 right giving us the answer.

4 0
3 years ago
How to simplify (n+2)!/n! <br><br> I will mark brainliest and give a thanks!
borishaifa [10]
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7 0
3 years ago
Write the first five terms of the the sequence defined by the explicit formula an=72(1/3)^n-1
lisabon 2012 [21]

a_n=72\left(\dfrac{1}{3}\right)^{n-1}\\\\\text{Put}\ n=1,\ n=2,\ n=3,\ n=4,\ n=5\ \text{to the equation}:\\\\n=1\to a_1=72\left(\dfrac{1}{3}\right)^{1-1}=72\left(\dfrac{1}{3}\right)^0=72(1)=72\\\\n=2\to a_2=72\left(\dfrac{1}{3}\right)^{2-1}=72\left(\dfrac{1}{3}\right)^1=72\left(\dfrac{1}{3}\right)=\dfrac{72}{3}=24\\\\n=3\to a_3=72\left(\dfrac{1}{3}\right)^{3-1}=72\left(\dfrac{1}{3}\right)^2=72\left(\dfrac{1}{9}\right)=\dfrac{72}{9}=8\\\\n=4\to a_4=72\left(\dfrac{1}{3}\right)^{4-1}=72\left(\dfrac{1}{3}\right)^3=72\left(\dfrac{1}{27}\right)=\dfrac{72}{27}=\dfrac{8}{3}\\\\n=5\to a_5=72\left(\dfrac{1}{3}\right)^{5-1}=72\left(\dfrac{1}{3}\right)^4=72\left(\dfrac{1}{81}\right)=\dfrac{72}{81}=\dfrac{8}{9}\\\\Answer:\ \boxed{72,\ 24,\ 8,\ \dfrac{8}{3},\ \dfrac{8}{9}}

8 0
3 years ago
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