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kobusy [5.1K]
3 years ago
7

What is N in 25-n=32?

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0
Simplify both sides of the equation.

<span><span>25−n</span>=32

</span><span>Simplify:

</span><span><span><span>−n</span>+25</span>=32

</span>Subtract 25 from both sides.

<span><span><span><span>−n</span>+25</span>−25</span>=<span>32−25

</span></span><span><span>−n</span>=7

</span>Divide both sides by -1.

<span><span><span>−n/</span><span>−1 </span></span>= <span>7/<span>−1

</span></span></span><span>n=<span>−7

</span></span>Ans:
<span>n = <span>−7</span></span><span>
</span>
expeople1 [14]3 years ago
4 0
N is Negative 7. If you add Negative 7 to 25, you get 32. Hope this helps, and good luck!!
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8 0
3 years ago
You play in a soccer tournament, that consists of 5 games. Each game you win with probability .6, lose with probability .3, and
nasty-shy [4]

Answer:

(a) The joint PMF of W, L and T is:

P(W,\ L,\ T)={5\choose (n_{W}!\times n_{L}!\times n_{T}!)}\times [0.60]^{n_{W}}\times [0.30]^{n_{L}}\times [0.10]^{n_{T}}

(b) The marginal PMF of W is:

P(W=w)={5\choose n_{W}!}\times 0.60^{n_{W}}\times (1-0.60)^{n-n_{W}}

Step-by-step explanation:

Let <em>X</em> = number of soccer games played.

The outcome of the random variable <em>X</em> are:

<em>W</em> = if a game won

<em>L</em> = if a game is lost

<em>T</em> = if there is a tie

The probability of winning a game is, P (<em>W</em>) = 0.60.

The probability of losing a game is, P (<em>L</em>) = 0.30.

The probability of a tie is, P (<em>T</em>) = 0.10.

The sum of the probabilities of the outcomes of <em>X</em> are:

P (W) + P (L) + P (T) = 0.60 + 0.30 + 0.10 = 1.00

Thus, the distribution of W, L and T is a appropriate probability distribution.

(a)

Now, the outcomes W, L and T are one experiment.

The distribution of <em>n</em> independent and repeated trials, each having a discrete number of outcomes, each outcome occurring with a distinct  constant probability is known as a Multinomial distribution.

The outcomes of <em>X</em> follows a Multinomial distribution.

The joint probability mass function of <em>W</em>, <em>L</em> and <em>T</em> is:

P(W,\ L,\ T)={n\choose (n_{W}!\times n_{L}!\times n_{T}!)}\times [P(W)]^{n_{W}}\times [P(L)]^{n_{L}}\times [P(T)]^{n_{T}}

The  soccer tournament consists of <em>n</em> = 5 games.

Then the joint PMF of W, L and T is:

P(W,\ L,\ T)={5\choose (n_{W}!\times n_{L}!\times n_{T}!)}\times [0.60]^{n_{W}}\times [0.30]^{n_{L}}\times [0.10]^{n_{T}}

(b)

The random variable <em>W</em> is defined as the number games won in the soccer tournament.

The probability of winning a game is, P (W) = <em>p</em> = 0.60.

Total number of games in the tournament is, <em>n</em> = 5.

A game is won independently of the others.

The random variable <em>W</em> follows a Binomial distribution.

The probability mass function of <em>W</em> is:

P(W=w)={5\choose n_{W}!}\times 0.60^{n_{W}}\times (1-0.60)^{n-n_{W}}

Thus, the marginal PMF of W is:

P(W=w)={5\choose n_{W}!}\times 0.60^{n_{W}}\times (1-0.60)^{n-n_{W}}

3 0
3 years ago
1345677865432+1234567890<br><br><br><br> CAN SOMEONE KILL THIS BRAINLY STUFF
Reptile [31]

Answer:

1.3469124e+12

Step-by-step explanation:

sure

7 0
3 years ago
A new pair of shoes is advertised for $110. The sales tax is 7.5%. What is the total cost of the shoes?
CaHeK987 [17]

Answer:

$118.25

Step-by-step explanation:

Always convert the percentage to a decimal by moving the decimal two points to the right/dividing by 100. So 7.5 % = 0.075

110 x 0.075 = 8.25 (the amount of tax added)

110 + 8.25 = 118.25

You can also multiply 110 by 1.075, where the "1" is the $110 and the ".075" is the tax, and save the step of adding. 110 x 1.075 = 118.25

8 0
3 years ago
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