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3 years ago

What is 2 1/3 + 1 3/4 equal to?

Mathematics

2 answers:

miss Akunina [59]3 years ago

5 0

10.25 hope this help you

Charra [1.4K]3 years ago

4 0

Answer:

4.0

Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

Given f(x) = x² + 2 and g(x) = x + 14<br>Find the values of a such that f(a) = g(a)

Minchanka [31]

Answer:

a = - 3, a = 4

Step-by-step explanation:

Given f(x) = x² + 2 and g(x) = x + 14 , then

f(a) = a² + 2 and g(a) = a + 14

For f(a) = g(a) , then equate the right sides

a² + 2 = a + 14 ( subtract a + 14 from both sides )

a² - a - 12 = 0 ← in standard form

(a - 4)(a + 3) = 0 ← in factored form

Equate each factor to zero and solve for a

a + 3 = 0 ⇒ a = - 3

a - 4 = 0 ⇒ a = 4

4 0

3 years ago

The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu

rjkz [21]

The balloon has a volume $V$ dependent on its radius $r$ :

$V(r)=\dfrac43\pi r^3$

Differentiating with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}$

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

$10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}$

The surface area of the balloon is

$S(r)=4\pi r^2$

and differentiating gives

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}$

so that at the moment the radius is 3 m, its area is increasing at a rate of

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}$

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3 years ago