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3 years ago

Loin has read 25 % of a book. If she has been reading for 5 hours, how many more hours will it take her to complete the book?

1 answer:

4 0

Well, the answer is 15 hours

Explanation:
Since it took Loin 5 hours to read 25% of the books and the entire book is 100%, 25% is 1/4 of the book. We add on 5 hours to every 1/4 of the book so 1/2=10 hours, 3/4= 15 hours and the entire book =20 hours. So the entire book would take 20 hours to read but the question is How many MORE hours so we subtract 5 hours from 20 hours which equals 15.

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Step-by-step explanation:

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2 years ago

There is a blizzard, and Matt notices that the snow is falling at a constant rate. Two hours after the beginning of the snowstor

MaRussiya [10]

Answer:

2 inches per hour, 5 inches, y=2x+5

Step-by-step explanation:

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3 years ago

A line has a slope of 10 and includes the points (3, n) and (4,0). What is the value of n? n =

ExtremeBDS [4]

Answer:

The value of n = -10

Step-by-step explanation:

Given the points

(3, n)

(4,0)

Finding the slope between (3, n) and (4,0)

$\left(x_1,\:y_1\right)=\left(3,\:n\right),\:\left(x_2,\:y_2\right)=\left(4,\:0\right)$

As slope = 10

using the formula

Slope = [y₂ - y₁] / [x₂ - x₁]

so substituting the values

10 = [0 - n] / [4 - 3]

10 = -n / 1

10 = -n

n = -10

Therefore, the value of n = -10

8 0

2 years ago

The slope of a linear function is 1/5. For every rise of 5 units, what is the run?

Jlenok [28]

Answer:

for every rise of 1 the run would be 25

7 0

2 years ago

Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random

Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

Let $\bar X$ = sample mean

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = $50,000

$\sigma$ = population standard deviation = $25,000

n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P( $\bar X$ > $52,000)

P( $\bar X$ > $52,000) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } }$ ) = P(Z > 2.53) = 1 - P(Z $\leq$ 2.53)

= 1 - 0.9943 = 0.0057

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0

3 years ago