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lord [1]
3 years ago
13

Stephen is testing the difference in means between time it takes to travel school in a bus and time it takes to travel to school

in a car. Stephen hypothesizes that it takes more time to travel in a bus. He calculates a p-value of 2%. He concludes at a 1% significance level that the true mean is greater for a bus than a car.
Where did Stephen go wrong in his conclusion? Explain in detail.
Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

Kindly check explanation

Step-by-step explanation:

To test for Difference in mean times

Null hypothesis, H0 will be, there is no difference in mean times ; m1 = m2

Alternative hypothesis, there is difference in mean times ; m1 ≠ m2

Decision region :

When p value < α ; reject the Null

Here. ;

Pvalue = 2% = 0.02

α = 1% = 0.01

Pvalue > α

0.02 > 0.01

Since, Pvalue > α ; we do not reject the Null ;

Hence, conclusion should be, there is no difference in mean times of bus and car

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Unctions.
ipn [44]

Answer:

im sorry cant help

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A smart phone manufacturer uses 10 ounces of gold circuitry to make 5,200 smart phones. If they made 7,800 smart phones last mon
padilas [110]

Answer:

$19,500

Step-by-step explanation:

In this question, the first thing we do

Is to calculate the amount of gold that was used in making 7,800 smartphones. We proceed as follows:

Firstly, 10 ounces made 5,200 smartphones, then x ounces will make 7,800 smartphones

Thus 10 * 7,800 = 5,200 * x

x = 78,000/5200 = 15 ounces

This means that 7,800 smartphones were made using 15 ounces of gold

Now, we know that the value of an ounce is $1,300. Thus, the value of 15 ounces would be 15 * 1,300 = $19,500

8 0
3 years ago
Please help me out if you can
Arlecino [84]

Answer:

(a, 0)

Step-by-step explanation:

Point S has the same x-coordinate as does Point R:  a.

Point S has the y-coordinate 0, as Point S lies on the x-axis.

Correct final answer:  (a, 0) represents Point S.

6 0
3 years ago
2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

  • That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
  • d = 112.5miles.

Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

  • His position is given as; S(b) = 90 × t

(a) For your friend to catch you, you both must be in the same position;

  • i.e S(a) = S(b)

75t + 112.5 = 90t

90t -75t = 112.5

t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

Read more:

brainly.com/question/24234606

6 0
2 years ago
Read 2 more answers
Multiply (3y^3+5y^2-4y) (2y^2-6y-7) help me solve this with the steps please
Gala2k [10]

Answer:

as following

Step-by-step explanation:

(3y^3+5y^2-4y) (2y^2-6y-7) \\=y(3y^2+5y-4)(2y^2-6y-7)\\=y(6y^4-16y^3-21y^2+10y^3-30y^2-35y-8y^2+24y+28)\\=y(6y^4-6y^3-59y^2-11y+28)\\=6y^5-6y^4-59y^3-11y^2+28y

3 0
3 years ago
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