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2 years ago

A 15-kg bag of strawberry for $8 ____ per kg

Mathematics

2 answers:

choli [55]2 years ago

7 0

Answer: $0.53 per kg

$0.53 per kilogram 8/15 = 53333333333.... round it

aleksandr82 [10.1K]2 years ago

4 0

Answer:

$0.53 per kg

Step-by-step explanation:

8/15=533333333... so round it

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Zolol [24]

We are asked to find 7 is what percent to 30.

We will use proportions to solve our given problem.

Let us assume that 7 is n% of 30. So we can set a proportion as:

$\frac{n}{100}=\frac{7}{30}$

Let us solve for n.

$\frac{n}{100}\cdot 100=\frac{7}{30}\cdot 100$

$n=\frac{7}{3}\cdot 10$

$n=\frac{70}{3}$

$n=23.333$

Therefore, 7 is $23.333\%$ of 30.

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11. El 9 de enero venden a crédito a Stan Lee Co las siguientes mercancías: 4

Allushta [10]

A AS

Step-by-step explanation:

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2 years ago

Which ratio expresses the scale used to create this drawing? The school has dimensions of 18 feet by 18 feet.

Papessa [141]

Answer A 1 square/2 feet=9 squares/18 feet

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2 years ago

Read 2 more answers

What's the fraction root of 9 over 49?

irakobra [83]

<span>√9/49

First you figure out the square root of 9 which is 3 since 3 x 3 equals 9. Then you find the square root of 49 which is 7 since 7 x 7 equals 49. Therefore, the answer is 3/7</span>

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2 years ago

Three moons are in the same circular orbit around a planet. The moons are each 120,000 kilometers from the surface of the planet

VladimirAG [237]

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

MN is the diameter of the planet which is $MN = 60000$

AM and NC are the distance of moons from the surface of the planet.

$AM = NC = 120000$

Since, angle ABC is given as 90 degree, it means, line AC will pass from the diameter of the planet.

So, distance between moon A and moon C is =

$AC=AM + MN + NC$

$AC = 120000+ 60000+ 120000$

$AC = 300000$

Hence the distance between point A and point C is 300000 Km. : Answer

Hope it will help :)

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2 years ago