Answer:
49π
Step-by-step explanation:
area of circle = πr^2
<em>Handy Tip: cherry pies delicious; apple pies are(R) too(2)! so C = πd and A = πr^2</em>
diameter = 14 cm
radius = 14/2 = 7cm
area of circle = π(7)^2
area of circle = 49π
Hope that helps!
Answer:
Step-by-step explanation:
<u>Find the measures of interior angles in each triangle</u>
Triangle BGC
The measures of triangle BGC are 
Triangle CGH
we know that
-----> by consecutive interior angles
we have that
so
substitute
we have
remember that
The measures of triangle CGH are 
Triangle GHE
remember that
substitute and solve for m<GEH
The measures of triangle GHE are 
RTP: [a tan(u) + b]² + [b tan(u) - a]² = (a² + b²) sec²(u)
Proving LHS = RHS:
LHS = [a tan(u) + b]² + [b tan(u) - a]²
= a² tan²(u) + 2ab tan(u) + b² + b² tan²(u) - 2ab tan(u) + a²
= (a² + b²) tan²(u) + (a² + b²)
= (a² + b²)[tan²(u) + 1]
= (a² + b²) sec²(u), using the identity: tan²(x) + 1 = sec²(x)
= RHS
The <em><u>correct answer</u></em> is:
They had no placeholding zero.
Explanation:
Our numbering system is one of few known to have a numeral for zero. Mayans did; however, theirs never traveled the world. Babylonians were thought to have a mark for nothing, but it was more for punctuation than numerals. Neither the Romans nor the Egyptians had a number for 0 either.
Zero is key to our system of numbering, as it helps us hold place as well as representing nothing. Without it, it is easier to represent problems in words.
No because x=4 and y=-5 and when you plug it in you get 5(4)+2(-5)=8 20+-10=8 and 10= does not work so it is not a possible solution.
