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kirill115 [55]
3 years ago
5

The types of problems found on ancient papyri, books, and tablets focuses primarily on problems that relate to daily life. The s

olution methods for many ancient cultures are generally verbal, with mathematical statements written out in words. Why did most ancient cultures primarily write out their mathematical texts in words?
Mathematics
2 answers:
Maksim231197 [3]3 years ago
8 0

The <em><u>correct answer</u></em> is:

They had no placeholding zero.

Explanation:

Our numbering system is one of few known to have a numeral for zero. Mayans did; however, theirs never traveled the world. Babylonians were thought to have a mark for nothing, but it was more for punctuation than numerals. Neither the Romans nor the Egyptians had a number for 0 either.

Zero is key to our system of numbering, as it helps us hold place as well as representing nothing. Without it, it is easier to represent problems in words.

olga55 [171]3 years ago
8 0
Because they had not developed algebraic language, which is the use of letters and symbols to represent quantities and their relation.
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Marina CMI [18]

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3 0
2 years ago
A marathon is 26.2 miles long. Jarrod is running a marathon and has completed 17.75 miles. How
Nana76 [90]

Answer:

Jarron has 8.45 more miles to get to the finish line.

Step-by-step explanation:

All we have to do is subtract the total number of miles by the number of miles Jarron has completed.

So: 26.20 - 17.75 = 8.45

5 0
3 years ago
In the lab, Alonzo has two solutions that contain alcohol and is mixing them with each other. Solution A is 6% alcohol and Solut
ioda

Answer:

200 mL

Step-by-step explanation:

If x is the volume of solution B:

0.06 (500) + 0.20 x = 0.10 (500 + x)

30 + 0.20 x = 50 + 0.10 x

0.10 x = 20

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4 0
3 years ago
Read 2 more answers
A support wire is attached to the top of a tower that is 65 feet tall as shown. If the wire makes an angle of 34 degree with the
Maru [420]
Answer:
length of wire = 116 ft

Explanation:
The attached image shows a diagram on the scenario given.

Now, we can note that the string forms a right-angled triangle with the tower and the ground. This means that special trig functions can be applied.
These functions are as follows:
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent

Now, from the given, we can find that:
θ = 34°
opposite is the tower = 65 ft
hypotenuse is the string length that we want to find

Substitute with the givens in the sin function to get the length of string as follows:
sin (34) = 65 / string
string = 65 / sin(34)
string = 116.2 which is approximately 116 ft

Hope this helps :)

8 0
3 years ago
Please help me ASAP!!! could someone help me do my geometry?
elena-14-01-66 [18.8K]

Answer:

9. m(YZ) = 102°

10. m(JKL) = 192°

11. m<GHF = 75°

Step-by-step explanation:

9. First, find the value of x

4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)

Collect like terms

4x - 3x = -3 + 15

x = 12

4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

4(12) + 3 = ½(m(YZ))

48 + 3 = ½(m(YZ))

51 = ½(m(YZ))

Multiply both sides by 2

51*2 = m(YZ)

102 = m(YZ)

m(YZ) = 102°

10. First, find the value of x.

7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)

Add like terms

13x + 11 = 180

13x = 180 - 11

13x = 169

x = 169/13

x = 13

7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

7(13) + 5 = ½(m(JKL))

96 = ½(m(JKL))

Multiply both sides by 2

2*96 = m(JKL)

m(JKL) = 192°

11. First, find x.

5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Multiply both sides by 2

2(5x + 15) = 11x + 18

10x + 30 = 11x + 18

Collect like terms

10x - 11x = -30 + 18

-x = -12

Divide both sides by -1

x = 12

m<GHF = 5x + 15

Plug in the value of x

m<GHF = 5(12) + 15

m<GHF = 60 + 15

m<GHF = 75°

4 0
3 years ago
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