Answer:
Jarron has 8.45 more miles to get to the finish line.
Step-by-step explanation:
All we have to do is subtract the total number of miles by the number of miles Jarron has completed.
So: 26.20 - 17.75 = 8.45
Answer:
200 mL
Step-by-step explanation:
If x is the volume of solution B:
0.06 (500) + 0.20 x = 0.10 (500 + x)
30 + 0.20 x = 50 + 0.10 x
0.10 x = 20
x = 200
Answer:length of wire = 116 ft
Explanation:The attached image shows a diagram on the scenario given.
Now, we can note that the string forms a right-angled triangle with the tower and the ground. This means that special trig functions can be applied.
These functions are as follows:
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
Now, from the given, we can find that:
θ = 34°
opposite is the tower = 65 ft
hypotenuse is the string length that we want to find
Substitute with the givens in the sin function to get the length of string as follows:
sin (34) = 65 / string
string = 65 / sin(34)
string = 116.2 which is approximately 116 ft
Hope this helps :)
Answer:
9. m(YZ) = 102°
10. m(JKL) = 192°
11. m<GHF = 75°
Step-by-step explanation:
9. First, find the value of x
4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)
Collect like terms
4x - 3x = -3 + 15
x = 12
4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
4(12) + 3 = ½(m(YZ))
48 + 3 = ½(m(YZ))
51 = ½(m(YZ))
Multiply both sides by 2
51*2 = m(YZ)
102 = m(YZ)
m(YZ) = 102°
10. First, find the value of x.
7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)
Add like terms
13x + 11 = 180
13x = 180 - 11
13x = 169
x = 169/13
x = 13
7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
7(13) + 5 = ½(m(JKL))
96 = ½(m(JKL))
Multiply both sides by 2
2*96 = m(JKL)
m(JKL) = 192°
11. First, find x.
5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Multiply both sides by 2
2(5x + 15) = 11x + 18
10x + 30 = 11x + 18
Collect like terms
10x - 11x = -30 + 18
-x = -12
Divide both sides by -1
x = 12
m<GHF = 5x + 15
Plug in the value of x
m<GHF = 5(12) + 15
m<GHF = 60 + 15
m<GHF = 75°