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disa [49]
3 years ago
11

Omar has 3 1/14 cups of dough to make dumplings.If he uses 3/16 cup of dough for each dumpling,how many whole dumplings can Omar

make?
Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

Omar can make 16 dumplings with some dough to spare

Step-by-step explanation:

you should convert each value to have the same denominator to make the equation easier

3 and 1/14 cups is the same as 43/14 cups of dough

so the total 43/14 needs to be divided by 3/16

43/14 divided by 3/16 = 43/14 * 16/3

=688/42 = 16.3809...

so Omar can make 16 dumplings with some dough to spare

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Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. A marble is
Reptile [31]

Answer:

a)2/7

b)1/2

c)9/14

d)6/7

Step-by-step explanation:

The jar contains 4 red marbles, numbered 1 to 4 which means

Red marbles = (R1) , (R2) , (R3) , (R4)

It also contains 10 blue marbles numbered 1 to 10 which means

Blue marbles = (B1) , (B2) , (B3) , (B4) , (B5) , (B6) , (B7) , (B8) , (B9) , (B10) .

We can calculate total marbles = 4red +10 blues

=14marbled

Therefore, total marbles= 14

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10) =7

Total number of Blue marbles = 10

Blue and even marbles = 5

(a) The marble is red

P(The marble is red)=total number of red marbles/Total number of marbles

=4/14

=2/7

(b) The marble is odd-numbered

Blue marbles with odd number= (B1) , (B3) , (B5) , (B7) , (B9) ,

Red marbles with odd number = (R1) , (R3)

Number of odd numbered =(5+2)=7

P(marble is odd-numbered )= Number of odd numbered/ Total number of marbles

P(marble is odd-numbered )=7/14

=1/2

(C) The marble is red or odd-numbered?

Total number of red marbles = 14

Number of red and odd marbles = 2

The marbles that has odd number = (R1) , (R3) ,(B1) , (B3) , (B5) , (B7) , (B9) =7

n(red or even )= n(red) + n(odd)- n(red and odd)

=4+7-2

=9

P(red or odd numbered)= (number of red or odd)/(total number of the marble)

= 9/14

(d) The marble is blue or even-numbered?

Number of Blue and even marbles = 5

Total number of Blue marbles = 10

Number of blue that are even= 5

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10)

=7

n(Blue or even )= n(Blue) + n(even)- n(Blue and even)

= 10+7-5 =12

Now , the probability the marble is blue or even numbered can be calculated as

P(blue or even numbered)= (number of Blue or even)/(total number of the marble)

= 12/14

= 6/7

6 0
3 years ago
An experiment consists of rolling a die, flipping a coin, and spinning a spinner divided into 7 equal regions. The number of ele
oee [108]

Answer:

Option A.

<em>The number of elements in the sample space of this experiment is 84</em>

Step-by-step explanation:

The sample space for an experiment represents the number of possible results that may occur when conducting the experiment.

When throwing a die and observe the number obtained there are 6 possible results

When throwing a coin there are 2 possible results.

When spinning a wheel divided into 7 regions we have 7 possible outcomes.

If we combine these three experiments, then the sample space S is composed of the product of the possible results of each experiment.

S = (6)(2)(7)\\\\S =84

5 0
3 years ago
Eugene can beat two levels every hour how many levels can he completed 3.5 hours
svlad2 [7]

Answer:

~6.5 Levels

Step-by-step explanation:

2 levels every hour = 2:1

we take that ratio and multiply it by 3 for starters:

6 and half of our ratio

basically 6.5

3 0
2 years ago
Pre-image point N(6,-3) was dilated to point N'(2, -1). What was the scale factor used?
Aleksandr [31]

Answer:

scale factor = \frac{1}{3}

Step-by-step explanation:

Consider the ratio of the x and y- coordinates, image to original, that is

scale factor = \frac{2}{6} = \frac{-1}{-3} = \frac{1}{3}

8 0
3 years ago
The imaginary number i is defined as ?<br><br> (1) -1<br> (3) √-4<br> (2) √-1<br> (4) (-1)²
Kryger [21]

Answer:

√-1

Step-by-step explanation:

The imaginary number i is defined as √(-1)

NOTE : i² = -1

8 0
2 years ago
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