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3 years ago

Which of the following equations is of a parabola with a vertex at (0, 6)?

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

y= x^2 + 6

Step-by-step explanation:

y= x2 + 6 (which should be written as y= x^2 + 6) has the form y - k = a(x - h)^2. For y= x^2 + 6, h = 0 and k = 6. Thus the vertex is (0, 6)

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ExtremeBDS [4]

Answer: m=6, m=-4

Step-by-step explanation:

To solve this proportion, we have to cross multiply.

$\frac{m-3}{7} =\frac{m}{m+8}$

$(m-3)(m+8)=7m$

Now that we have cross multiplied, we actually need to FOIL the left side to expand the equation.

$m^2+8m-3m-24=7m$

Combine like terms.

$m^2+5m-24=7m$

We can move all terms to one side and then solve for m.

$m^2-2m-24=0$

We can actually factor this to:

$(m-6)(m+4)=0$

We set each factor equal to 0 to find m.

m-6=0

m=6

m+4=0

m=-4

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