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zaharov [31]
2 years ago
7

If −1 is a zero of the polynomial p(x)=ax^3−x^2+x+4, find the value of a.

Mathematics
1 answer:
vitfil [10]2 years ago
8 0

Answer:

a = 2

Step-by-step explanation:

given x = - 1 is a zero then f(- 1) = 0 , that is

a(- 1)³ - (- 1)² - 1 + 4 = 0

- a - 1 - 1 + 4 = 0

- a + 2 = 0 ( subtract 2 from both sides )

- a = - 2 ( multiply both sides by - 1 )

a = 2

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3 years ago
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3 years ago
Read 2 more answers
6. Explain why &lt;1 = &lt;2.
slavikrds [6]

Step-by-step explanation:

Since AC=BE & DE=DC

then measure angle <CAD=<EBD =X

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8 0
2 years ago
PLEASE HELP!!!!!!
slava [35]

9514 1404 393

Answer:

  A: (3x +4)

  B: (4x +5y) × (4x -5y)

Step-by-step explanation:

<u>Part A</u>:

Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.

  9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²

The side of the square is 3x+4.

__

<u>Part B</u>:

The difference of squares is factored like this:

  a²-b² = (a +b)(a -b)

The given area expression is the difference of squares with ...

  a = 4x, b = 5y

so, the factorization is ...

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The dimensions of the rectangle are (4x+5y) by (4x-5y).

3 0
3 years ago
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