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sveticcg [70]
3 years ago
6

How many times does 3 go into 9

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
8 0
3 times I hope I help you
AVprozaik [17]3 years ago
5 0
3 go into 9 3 times
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In a computer game, a bird flies at a height of 1,281 feet. At the same time, a fish swims 282 feet below sea level. What is the
fenix001 [56]
To find the difference, we need to subtract the height of the fish from the height of the bird. If we use sea level as 0, then the bird flies at 1,281 feet, and the fish swims at -282 feet.

1,281 - (-282) = <span>1,281 + 282 = 1,563 feet

There is a </span><span>1,563 feet difference between the height of the bird and the depth of the fish</span>
6 0
3 years ago
Read 2 more answers
If M is the set of all square of integers that are less than 100 and N is the set of all positive odd numbers that are under 15,
ollegr [7]

A set is simply the group of numbers.

  • <em>The set of M and N are: </em>M = \{1,4,9,16,25,36,49,64,81\}<em>  and </em>N= \{1,3,5,7,9,11,13\}<em>.</em>
  • <em>The set of M n N is: </em>M\ n\ N = \{1,9\}<em>.</em>
  • <em>The set of  M u N is: </em>M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}<em />

<u>(a) The set of M and N</u>

Given that:

M = squares of integers less than 100

N = Positive odd numbers less than 15

So, we have:

M = \{1,4,9,16,25,36,49,64,81\}

N= \{1,3,5,7,9,11,13\}

<u>(b) M n N and M u N</u>

M n N is the set of common elements between sets M and N.

So, we have:

M\ n\ N = \{1,9\}

M u N is the set of all elements in sets M and N.

So, we have:

M\ u\ N = \{1,3,4,5,7,9,11,13,16,25,36,49,64,81\}

Read more about sets at:

brainly.com/question/2332158

8 0
2 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=20$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0
3 years ago
My shadow in the back. Yeah no I need help. One again.
Neporo4naja [7]

1 2/5 - (-3/5)

First, we're going to convert 1 2/5 into an improper fraction.

1 2/5 = 7/5

7/5 - (-3/5)

Subtracting a negative is the same as adding, so the problem will look like:

7/5 + 3/5

The denominators are the same, so we just add the numerators.

The answer is 10/5, or 2.

7 0
3 years ago
Show steps <br> Simplify <img src="https://tex.z-dn.net/?f=%5Csqrt%7B81%7D" id="TexFormula1" title="\sqrt{81}" alt="\sqrt{81}" a
AysviL [449]
The square root of 81 is 9
4 0
2 years ago
Read 2 more answers
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