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11111nata11111 [884]
3 years ago
11

I need help please! ​

Mathematics
1 answer:
Sophie [7]3 years ago
4 0

Answer/Step-by-step explanation:

Area of trapezium = ½*(AD + BC)*AB

Area = 42 cm²

AD = (x + 8) cm

BC = (x + 5) cm

AB = x cm

Plug in the values into the equation

42 = ½((x + 8) + (x + 5))*x

42 = ½((x + 8 + x + 5)*x

42 = ½(2x + 13)*x

Multiply both sides by 2

42*2 = (2x + 13)*x

84 = 2x² + 13x

2x² + 13x = 84

Subtract both sides by 84

2x² + 13x - 84 = 0

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Pls help me !! will mark brainliest... i just need you to solve for m<1 and m<7 !! thanks !!
frez [133]

Step-by-step explanation:

=( n-2)180

= ( 4 - 2 )180

= 360

So, 144 + 90 + m<2 +m<1 = 360

144 + 90 + 85 + m<1 = 360

319 + m<1 = 360

m<1 = 360 - 319

m<1 = 41

their is an unknown angle so let's call it x

let's find x first ( m<6=49)

x + m<6 = 180

x + 49 = 180

x = 180 - 49

x = 131

Now let's find m<7

m<7 + 38 + m<4 + x = 360

m<7 + 38 + 85 + 131 = 360

m<7 + 254 = 360

m<7 = 360 - 254

m< 7 = 106

8 0
3 years ago
Need geometry help ASAP please!
tatiyna

Answer:

1. 121 π  unit²

2. 143°

3. 151 unit²

Step-by-step explanation:

1.

Area of a circle is given by the formula  A = πr²

where

A is the area,

r is the radius of the circle

From the given diagram, we can see that the radius is 11, hence the area will be:

A=\pi r^2\\A=\pi (11)^2\\A=121\pi

The answer is  121\pi units^2

2.

The unshaded secctor and the shaded sector equals the circle. We know that circle is 360°. The unshaded sector has an angle of 217°. So the shaded part will be 360 - 217 = 143°

The measure of the central angle of the shaded sector is 143°

3.

Area of a sector is given by the formula  A=\frac{\theta}{360}*\pi r^2

Where

\theta is the central angle of the sector (in our case it is 143°)

r is the radius (which is 11)

Plugging in all the info into the formula we have:

A=\frac{\theta}{360}*\pi r^2\\A=\frac{143}{360}*\pi (11)^2\\A=150.99

<em>rounding to the nearest whole number, it is </em>151 units^2

3 0
3 years ago
Which theorem or postulate justifies that angle HEF ~ angle HGE ?
Levart [38]
Based on the picture above,
The theorem or postulate that justifies that Angle HEF ~ angle HGE is :
A. AA similarity postulate
(s is used for equal side, that is used for congruent)

hope this helps
5 0
3 years ago
When QS=6x and CS=5x-8, what is AB?
patriot [66]

Answer:

AB = x+ 8

Step-by-step explanation:

Given : QS=6x and CS=5x-8

From the given figure,

QS = QC + CS

We are given with  QS  and CS

Replace it the above equation

6x = QC + 5x -8

Solve for QC

Subtract 5x on both sides

x = QC + -8

Add 8 on both sodes

QC= x + 8

QABC is a rectangle

QC = AB

So AB = x+ 8


4 0
3 years ago
Trigonometry heeellllppp plzzzz​
algol [13]

Answer:

x ≈ 3.4 cm

Step-by-step explanation:

Using the sine ratio in the right triangle

sin57° = \frac{opposite}{hypotenuse} = \frac{x}{4} ( multiply both sides by 4 )

4 × sin57° = x , thus

x ≈ 3.4 cm ( to 1 dec. place )

3 0
3 years ago
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