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julsineya [31]
3 years ago
6

A cell phone company is looking to place a new tower to service 3 cities. In order for it to best service each city, it needs to

be equidistant from all 3 cities. What mathematical concept could they use to find a location that is equidistant from all 3 cities? Why is this a good method?
Mathematics
1 answer:
omeli [17]3 years ago
7 0

Answer:

  • circumscribed circle
  • The center of a circle circumscribing the triangle connecting the 3 cities will be equidistant from all three cities.

Step-by-step explanation:

The circumscribed circle or <em>circumcircle</em> of a polygon is a circle that passes through all the vertices of the polygon. The center of the circle, the circumcenter, is equidistant from all of the polygon's vertices.

The center is found at the point of intersection between the perpendicular bisectors of any two (non-parallel) chords of the circle. That is, <em>the perpendicular bisectors of any two of the sides of the triangle joining the cities will intersect at the circumcenter</em>.

The method of locating the center of the circle this way is simple and effective.

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Answer:

Step-by-step explanation:

For example, the base-8 numeral 23-8 contains two digits, "2" and "3", and with a base number (subscripted) "8". When converted to base-10, the 23-8 is equivalent to 19-10, i.e. 23-8 = 19-10.

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Answer:

6 is from the beginning. Multiply first, not add

Step-by-step explanation:

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4 years ago
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Help me please I’m so confused ):
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The domain is all the x-values you can use with this function. When dealing with a function like this, you need to ask yourself, what would make the bottom equal to 0? Whatever those numbers are, you do NOT want them in your domain.

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Eva8 [605]

Answer:

x+y=29

70x+80y=2130

x=19 and y=10

Step-by-step explanation:

the amount of tickets he sold is 29 which includes VIP and general admission tickets so the number of tickets sold for each would be x+y=29.

the price for general admission is 70$ and VIP is 80$. the profit from the tickets is 2130$ so that would be the number of general tickets (x) times the price (70) and the number of VIP tickets (y) times the price (80) so that would be 80y. therefore you're equation would be 70x+80y=2130. that is your system of equations.

To figure out the number of tickets for each: Solve x+y=29 for x:

x+y=29

x+y+−y=29+−y(Add -y to both sides)

x=−y+29

Substitute−y+29 for xi n70x+80y=2130:

70x+80y=2130

70(−y+29)+80y=2130

10y+2030=2130 (Simplify both sides of the equation)

10y+2030+−2030=2130+−2030 (Add -2030 to both sides)

10y=100

10y/10=100/10 (Divide both sides by 10)

y=10

Substitute 10 for y in x=−y+29:

x=−y+29

x=−10+29

x=19 (Simplify both sides of the equation)

Answer: x=19 and y=10

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