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murzikaleks [220]
3 years ago
13

You roll three six-sided dice. What is the probability that exactly two of the dice are odd? Write your answer as a fraction in

simplest form.
The probability is
Mathematics
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

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A ruby throated hummingbird beat its wings about 53 times each second about how many times does a ruby throated hummingbird beat
Sergeeva-Olga [200]
You would cross multiply 53 times 5 and divide by 1
3 0
3 years ago
John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid
tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

so

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

7 0
2 years ago
Read 2 more answers
Here you go this is the full question please help
hammer [34]
I don’t see anything is there supposed to be a picture or?
8 0
2 years ago
Read 2 more answers
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
Find dy/dx | x=-2, given that y=4+4x^2<br><br> Dy/dx| x=-2 =
-Dominant- [34]
Hmmmmmmmmmmmmmmmmmmmmmmmmm
7 0
2 years ago
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