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murzikaleks [220]
3 years ago
13

You roll three six-sided dice. What is the probability that exactly two of the dice are odd? Write your answer as a fraction in

simplest form.
The probability is
Mathematics
1 answer:
Alenkinab [10]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

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25)
Liula [17]

Answer:

A) w=3

Step-by-step explanation:

4 x 3 = 12

This is the work when you plug in the numbers in the varible w

6 0
3 years ago
Read 2 more answers
Find the length of the arc.
Arte-miy333 [17]
  • radius=r=7in
  • Angle=135°

We know

  • Length if arc=L

\boxed{\sf L=\dfrac{\theta}{360}\times 2πr}

\\ \sf\longmapsto L=\dfrac{135}{360}\times2π(7)

\\ \sf\longmapsto L=\dfrac{27}{72}\times 14π

\\ \sf\longmapsto L=\dfrac{27}{36}\times 14π

\\ \sf\longmapsto L=\dfrac{9}{12}\times 7π

\\ \sf\longmapsto L=\dfrac{63π}{12}

\\ \sf\longmapsto L=\dfrac{21π}{4}in

6 0
3 years ago
Please answer this question please ​
Bas_tet [7]
<h3>Answer:</h3><h3 /><h3>Amount = Rs 13891.50</h3><h3>Compound interest = Rs 1891.50</h3>

Step-by-step explanation:

C = Amount (A) - Principal (P)

Where

C is the compound interest

To find the amount we use the formula

A = P ({1 +  \frac{r}{100} })^{n}

where

P is the principal

r is the rate

n is the period / time

From the question

P = Rs 12, 000

r = 5%

n = 3 years

Substitute the values into the above formula

That's

A = 12000 ({1 +  \frac{5}{100} })^{3}  \\ A = 12000(1 + 0.05)^{3}  \\ A = 12000 ({1.05})^{3}

We have the answer as

<h3>Amount = Rs 13891.50</h3>

Compound interest = 13891.50 - 12000

<h3>Compound interest = Rs 1891.50</h3>

Hope this helps you

8 0
3 years ago
URGENt! PLS HELP. DONT USE LINKS OR JOKE. SEND REAL ANSWER. ITS VOLUME.
Nata [24]

Answer:

334

Step-by-step explanation:

8 0
3 years ago
Start with the logistic equation dx dt kx(M−x). Suppose we modify our harvesting. That is we will only harvest an amount proport
Marina CMI [18]

Answer:

a) dx/dt = kx*(M - h/k - x)

Step-by-step explanation:

Given:

- The harvest differential Equation is:

                            dx/dt = kx*(M-x)

Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In  other  words  we  harvest hx per  unit  of  time  for  some h > 0

Find:

a) Construct the differential equation.  

b) Show that if kM > h, then the equation is still logistic.

c) What happens when kM < h?

Solution:

- The logistic equation with harvesting that is proportional to population is:

                               dx/dt = kx*(M-x) hx

It can be simplified to:

                              dx/dt = kx*(M - h/k - x)

- If kM > h, then we can introduce M_n=M -h/k >0, so that:

                              dx/dt = kx*(M_n  - x)  

Hence, This equation is logistic because M_n >0

- If kM < h,  then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n  - x)  < 0 for all x<0 then the population will tend to zero for all initial conditions

6 0
3 years ago
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