False.
6(x)+434=?
x= number of hours so problem can be rewritten as
6(37)+434
———
222+434=
656
Answer:
The average yearly growth o
Explanation:
Given that the tree grew from 18 ft 35 1/2 feet in 3 1/2 years.
The growth within these years is:
35 1/2 - 18
= 35.5 - 18
= 17.5
Now, this averages:
17.5/3.5 (3.5 is the number of years)
= 5
The average is 5 ft per year
Answer:
2.5833333333333333333
Step-by-step explanation:
Use the power, product, and chain rules:

• product rule

• power rule for the first term, and power/chain rules for the second term:

• power rule

Now simplify.

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.
On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

Differentiate both sides and you end up with the same derivative:
