Solve for x. x^2=1/4

Mathematics

2 answers:

inessss [21]3 years ago

5 0

Answer:

c) x= +/- 1/2

tangare [24]3 years ago

4 0

Answer:

x= 1/2 or - 1/2

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I really need help thia is my last chance to get a good grade in math-

romanna [79]

Answer:

Step-by-step explanation:

bsahaahaaana

8 0

3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago

Help

Art [367]

$\huge\fbox{Answer ☘}$

$\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3} \times - 1} = 2( \frac{32}{243} ) {}^{2x} }\\ \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times - 1 } = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x} \\\\ 3( \frac{3}{2} ) {}^{2 \times - 1} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{2}{3} ) {}^{2} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x} \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x = \frac{1}{5} }$