Question

Which quadratic equation defines the function that has zeros at − 1/12 and 1/4 ?

Answer 1

$\bf \begin{cases} x=-\frac{1}{2}\implies &x+\frac{1}{2}=0\\\\ x=\frac{1}{4}\implies &x-\frac{1}{4}=0 \end{cases} \\\\\\ \left( x+\frac{1}{2} \right)\left( x-\frac{1}{4} \right)=\stackrel{y}{0}\implies \stackrel{FOIL}{x^2+\frac{1}{4}x-\frac{1}{8}}=y$