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3 years ago

Which quadratic equation defines the function that has zeros at − 1/12 and 1/4 ?

1 answer:

7 0

$\bf \begin{cases}
x=-\frac{1}{2}\implies &x+\frac{1}{2}=0\\\\
x=\frac{1}{4}\implies &x-\frac{1}{4}=0
\end{cases}
\\\\\\
\left( x+\frac{1}{2} \right)\left( x-\frac{1}{4} \right)=\stackrel{y}{0}\implies \stackrel{FOIL}{x^2+\frac{1}{4}x-\frac{1}{8}}=y$

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The scatter plot above show the relationship between the number of bags of popcorn that are sold and the price per bag. Which is

saul85 [17]

The independent variable is is the price per bag.

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3 years ago

(9-a+5a)/c (a=6,c=9)

SIZIF [17.4K]

$\frac{9-a+5a}{c} = \frac{9-(6)+5(6)}{(9)}= \frac{3+30}{9} = \frac{33}{9} = \frac{11}{3}$

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2 years ago

What is the distance between (2,-9) and (-1,4)

kkurt [141]

Answer:

total distance might be 16

Step-by-step explanation:

|y2-y1/x2-x1|, plug it the numbers, if you got a negative number, its just positive since the equation is set to absolute value

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2 years ago

Please help ASAP!!!!!!!!

JulijaS [17]

The correct answer is: "The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35."

Step-by-step explanation:

When numbers are considered, their position or place value matters a lot.

When a decimal number is written, moving left from the decimal point the place value increases ten times and while moving to the right the place value decreases 10 times.

Given two numbers are:

50.8 and 18.35

In order to compare the 5 in both numbers we have to find the place value of 55 in both numbers.

So,

In 50.8:

The place value of 5 in 50.8 is: 50

In 18.35:

The place value of 5 will be: 5/100

To compare the values, we will divide the larger place value by smaller place value

$=\frac{50}{\frac{5}{100}}\\\\=\frac{50*100}{5}\\\\= \frac{5000}{5}\\\\=1000\ times$

Hence,

The correct answer is: "The value of the 5 in 50.8 is 1,000 times the value of the 5 in 18.35."

Keywords: Place value, decimals

Learn more about place values at:

#LearnwithBrainly

4 0

3 years ago

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

MAXImum [283]

f(k) = k2 + 2k + 1 = (k+1)^2
The range is what the function gives to you f(k)=25=5^2 or (-5)^2
f(k)=64=8^2 or (-8)^2

You need to find the k values for these boundary values to find the domain.
Good luck :)

7 0

2 years ago