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3 years ago

15

Which quadratic equation defines the function that has zeros at − 1/12 and 1/4 ?

1 answer:

Cerrena [4.2K]3 years ago

7 0

$\bf \begin{cases}
x=-\frac{1}{2}\implies &x+\frac{1}{2}=0\\\\
x=\frac{1}{4}\implies &x-\frac{1}{4}=0
\end{cases}
\\\\\\
\left( x+\frac{1}{2} \right)\left( x-\frac{1}{4} \right)=\stackrel{y}{0}\implies \stackrel{FOIL}{x^2+\frac{1}{4}x-\frac{1}{8}}=y$

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