Answer:
The answer is 1/2 ans....
Answer:
-42/11
Step-by-step explanation:
x = y - 8
5x = 6 - 6y
So now solve the system of equations, divide everything in the second equation by 5 to get it to x = 6/5 - 6y/5
Now...
x = y - 8
x = 6/5 - 6y/5
Now substitute first equation into the second and x is gonna be -42/11 or the first number
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange x - 2y = - 3 into this form
Subtract x from both sides
- 2y = - x - 3 ( divide all terms by - 2 )
y =
x +
← in slope- intercept form
with m = 
• Parallel lines have equal slopes, thus
y =
x + c ← is the partial equation
To find c substitute (- 1, 2) into the partial equation
2 = -
+ c ⇒ c = 2 +
= 
y =
x +
← in slope- intercept form
Multiply through by 2
2y = x + 5 ( subtract 2y from both sides )
0 = x - 2y + 5 ( subtract 5 from both sides )
- 5 = x - 2y, thus
x - 2y = - 5 ← in standard form
The answers are B & C.
First thing to d
o is convert Radians to Degrees. 1 radians = 180/pi
. So, 3.5 radians times 180 divided by

= 200.5352283 or which could be rounded of to 200.54. Thus, confirming choice letter C and negating choices A and D.
Next thing to check is choice letter B. To do this, we need to convert the decimal value of the computed answer which is 0.5352283 to minutes and seconds by the following conversion factors.
1 degree = 60 mins
1 minute = 60 seconds
Now, we multiply 0.5352283 by 60 to get 32.113698 minutes, thus
32 minutesthen multiply 0.113698 by 60 to get 6.82188 ~
7 seconds.therefore, conversion would yield an answer 200 degrees 32 minutes and 7 seconds.