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LUCKY_DIMON [66]
3 years ago
11

What is the equation of the line that passes through the points (-3,4) and (6,7)

Mathematics
2 answers:
inn [45]3 years ago
6 0
Y=mx+b, m=(y2-y1)/(x2-x1)

m=(7-4)/(6--3)=3/9=1/3

y=x/3 +b, now use either point to solve for b, I'll use (6,7)

7=6/3 +b

7=2+b

b=5 so our line is:

y=x/3 +5 or more neatly...

y=(x+15)/3
stellarik [79]3 years ago
6 0
The first think you have to do is find the slope. This is found by (y2-y1)/(x2-x1) using these two points, this gives a slope (m) of 1/3. This will be plugged into the point slope equation y-y1=m(x-x1) this gives an equation of y-7=1/3(x-6) or Y=1/3x+5
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Need help ASAP !!! And show work please
sammy [17]

Answer:

\sqrt{40} or 6.32

Step-by-step explanation:

We can find the distance between two points by using this formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

where the x and y values are derived from the given points

The points given are ( -2 , 5 ) and ( 4 , 3 )

So we plug in the x and y values of those coordinates into the distance formula

\sqrt{(4-(-2)^2+(3-5)^2} \\4-(-2)=6\\3-5=-2\\d=\sqrt{6^2+-2^2} \\6^2=36\\-2^2=4\\36+4=40\\d=\sqrt{40}

or 6.32

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