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3 years ago

Please help ASAP ! Right answer only.

Mathematics

1 answer:

marissa [1.9K]3 years ago

6 0

Answer:

x + 4y

Step-by-step explanation:

(x∧2+8xy+16y∧2)∧(1/3) · (x+4y)∧(1/3) = ((x+4y)∧2 · (x+4y))∧(1/3) = ((x+4y)∧3)∧(1/3)=

= (x+4y)∧(3/3) = x+4y

Good luck!!!

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(SAT Prep) If the lengths of two sides of a triangle are 5 and 9 which would be length of the third side?

julia-pushkina [17]

The length of third side of triangle is 4 or 14.

According to the statement

we have given that the two sides of the triangle which are 5 and 9 and we have to find the length of the third side of triangle.

So, For this purpose, we know that the

If we had a triangle with sides a, b and c, then we can say

b-a < c < b+a

where b is larger than 'a'. This is the triangle inequality theorem

In this case, a = 5 and b = 9 so,

b-a < c < b+a

9-5 < c < 9+5

4 < c < 14

Telling us that c is some number between 4 and 14, not including either endpoint. If c is a whole number, then c could be any value from this set.

And

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1 year ago

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3 years ago

If f(x)=3x+10x and g(x)=4x-1 find (f-g)(x)

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Answer:

(f - g)(x) = 9x + 1

Step-by-step explanation:

Step 1: Write out functions

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4 years ago

A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his s

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Answer:

d) The difference exists due to chance since the test statistic is small

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From the given information:

Population mean = 178 cm

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the standard deviation = 2

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The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

$H_o: \mu = 178$

Alternative hypothesis:

$H_1: \mu \neq 178$

The t-test statistics is determined by using the formula:

$t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}$

$t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}$

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$\mathbf{t= -1.25}$

Degree of freedom df = n- 1

Degree of freedom df = 25 - 1

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At the level of significance ∝ = 0.05, the critical value = 2.064

Decision rule: To reject the null hypothesis if the test statistics is greater than the critical value at 0.05 level of significance

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Answer:

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