Area=(Theta/2) * r^2 This should be it, obviously Theta is your angle and you should use radiants in theory.
Hello,
8+h>2+3h
==>-2h>2-8
==>-2h>-6
==>h<3
Answer C
The answers are
1. 18
2. 1 1/15
If its the one under the one with a written answer(the first on blank at the top) its b. 20% did not arrive.
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2
The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2
