Find the widest range of scores that you can get on a final exam in order to receive a grade of B for the class. Using interval
notation
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Need answer asap!!
2 answers:
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Answer:
- y = -2(x -3)² +24
- 16 feet
Step-by-step explanation:
We expect the equation for y to be quadratic. Since the table is obviously symmetrical about x=3, we can start with the vertex form ...
y = a(x -3)² +b
Filling in the values from the first two table points, we get
For (x, y) = (0, 6):
6 = a(0 -3)² + b ⇒ 9a +b = 6
For (x, y) = (2, 22):
22 = a(2-3)² +b ⇒ a +b = 22
Subtracting the second equation from the first gives ...
(9a +b) -(a +b) = (6) -(22)
8a = -16 . . . . . . collect terms
a = -2 . . . . . . . . divide by 8
The second equation above tells us ...
b = 22 -a = 22 -(-2) = 24
So, our equation for y is ...
y = -2(x -3)² +24
__
The value of y for x=5 is ...
y = -2(5 -3)² +24 = 16
The height of the ball after 5 seconds is 16 feet.
Answer: About 191 students scored between a 60 and an 80.
Step-by-step explanation:
Given : A set of 200 test scores are normally distributed with a mean of 70 and a standard deviation of 5.
i.e. and
let x be the random variable that denotes the test scores.
Then, the probability that the students scored between a 60 and an 80 :
The number of students scored between a 60 and an 80 = 0.9544 x 200
= 190.88 ≈ 191
Hence , about 191 students scored between a 60 and an 80.
Answer:
We'll use the Law of Sines:
Sine (C) / c = Sine (B) / b
Sine (86) / 40 = Sine (52) / b
0.99756 / 40 = 0.78801 / b
0.024939 = .78801 / b
b = .78801 / .024939
side b = 31.5974978949 feet
Sine (42) / a = Sine (86) / 40
(0.66913 / a) = 0.024939
a = .66913 / .024939
side a = 26.8306668271 feet
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I forgot to include the graphic.
Step-by-step explanation:
