Hello! remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I'll choose the figure below in order to illustrate this problem. A composite polygon is a polygon that can be divided into two or more basic shapes. So here we have a composite polygon formed by a triangle and a rectangle. So:

$A_{total}=A_{T} \\ \\ A_{triangle}=A_{tr} \\ \\ A_{rectangulo}=A_{r} \\ \\ \\ A_{tr}=\frac{b\times h}{2} \\ \\ b:Base \ of \ the \ triangle \\ \\ h:height \ of \ the \ triangle \\ \\ \\ A_{r}=B\times H \\ \\ B:base \ of \ the \ rectangle \\ \\ H:height \ of \ the \ rectangle$

So the area of the composite figure is:

$A_{T}=\frac{16\times 11}{2} + 16\times 18 \\ \\ A_{T}=88+288 \\ \\ \boxed{A_{T}=376 \ m^2}$

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Dilation: brainly.com/question/10946046

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8 0

3 years ago

(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).

frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0

1 year ago

Find the measure of the indicated arc

dimaraw [331]

Answer:

arc of WXY= 224°

Step-by-step explanation:

measure of angle C is half of the WXY arc

this means WXY×1/2=C

112°=1/2 WXY (cross production)

WXY=2×112°

WXY=224 °

5 0

3 years ago