To get the answer we have to tranform into y=ax+b form
-2x+4y=68 /+2x
4y=2x+68 /:4
y= $\frac{1}{2} x+17$ - its the result

13x+4y=284 /-13x
4y=-13x+284 /:4
y= $- \frac{13}{4}+ 71$
y=- $3 \frac{1}{4}x+71$ - its the result

8 0

3 years ago

given the function f(x)=x^3 +x^2-2x+1 what is the resulting function f(x) is shifted to the left one unit

Nadya [2.5K]

Answer:

The resulting function is $f(x+1) = x^3 + 4x^2 + 3x + 1$

Step-by-step explanation:

Suppose we have a function f(x). If we want to shift the function 1 unit to the left, we find f(x+1).

In this question, we have:

$f(x) = x^3 + x^2 - 2x + 1$

Shifting 1 unit to the left:

$f(x+1) = (x+1)^3 + (x+1)^2 - 2(x+1) + 1$

$f(x+1) = (x^3 + 3x^2 + 3x + 1) + (x^2 + 2x + 1) - 2x - 2 + 1$

$f(x+1) = x^3 + (3+1)x^2 + (3+2-2)x + 1 + 1 - 2 + 1$

$f(x+1) = x^3 + 4x^2 + 3x + 1$

The resulting function is $f(x+1) = x^3 + 4x^2 + 3x + 1$

8 0

2 years ago