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blondinia [14]
2 years ago
5

What time is half an hour before a quarter to 3

Mathematics
1 answer:
V125BC [204]2 years ago
6 0

2:15


Half an hour is 30 minutes

A quarter is 15 minutes

A quarter to 3 is 2:45

Half an hour before 2:45 is 2:15

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
2 years ago
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Answer: 12x^3 y^6

Step-by-step explanation: Have a nice day! -Lily ^-^

5 0
2 years ago
Write y=-3x^2+12x-21 in vertex form
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Complete the square: 
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<span>y = 3(x^2 - 4x + 4 - 4) + 4 </span>
<span>y = 3(x^2 - 4x + 4) - 12 + 4 </span>
<span>y = 3(x - 2)^2 - 8</span>
5 0
2 years ago
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What is the range of this data<br> (3,3,08,7,10,2,6,12,0)<br> A 7.5<br> B 6.5<br> C 10<br> D 12
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The range is 12. (12-0)
6 0
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Mark wants to find the area of a circle with a diameter of 6 cm. Which expressions can he use to find the area of the circle in
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Answer:

B and C

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