Formula for this case is
(a+b)∧3=a∧3+3a∧2b+3ab∧2+b∧3
(2x+5)∧3=(2x)∧3+3*(2x)∧2*5+3*2x*5∧2+5∧3=8 x∧3+3*4x∧2*5+3*2x*25+125=
=8x∧3+60x∧2+150x+125
Good luck!!!
D is the answer as the both have solution x=-2 y=3
14x=-28 12(-2)-3y=-33
x=-2 -3y=-9
y=3
from the given equation
4x-y=11 eq 1
2x+3y=5 eq 2
x=y-11/4 from equation 1
subsitute this value of x in equation 2
2(y-11/4)+3y=5
y-11+6y=10
7y-11=10
y=3
subsitude this value of y in equation (x=y-11/4)
so x= -2
thus same solution so ANSWER IS D
Answer:
Yes, It is!
Step-by-step explanation:
Answer:
x=−3 or x=5
Step-by-step explanation:
x2−2x−15=0
Step 1: Factor left side of equation.
(x+3)(x−5)=0
Step 2: Set factors equal to 0.
x+3=0 or x−5=0
x=−3 or x=5
