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3 years ago

Can someone please help me?! Marking Brainliest!!!!!

Mathematics

2 answers:

irga5000 [103]3 years ago

3 0

Answer:

$5\sqrt{2}$

Step-by-step explanation:

The formula for the length of a vector/line in your case.

$L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}$

aleksklad [387]3 years ago

3 0

Answer: Mark them BRAINLIEST

Step-by-step explanation:

Because they helped my little sister out and they deserve it! :D

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3 years ago

When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval

Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

$\alpha = 1-99$ %

$=1-0.99$

$=0.01$

then,

$\frac{\alpha}{2} =\frac{0.01}{2}$

$=0.005$

or,

$Z_{\frac{\alpha}{2} }=Z_{0.005}$

$=2.576$

Now,

The point estimate will be:

⇒ $\hat{P}=\frac{x}{n}$

⇒ $=\frac{110}{343}$

⇒ $=0.321$

or,

⇒ $1-\hat{P}=1-0.321$

⇒ $=0.679$

The margin of error will be:

⇒ $E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )$

On substituting the above values, we get

⇒ $=2.576\times \sqrt{\frac{0.321\times 0.679}{343} }$

⇒ $=2.576\times \sqrt{\frac{0.217959}{343} }$

⇒ $=0.065$

hence,

⇒ $\hat{P}-E$

⇒ $0.321-0.065$

⇒ $0.256,0.386$

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3 years ago