Answer:
Projective tests are a type of personality test that is designed to have a person react to ambiguous stimuli to potentially reveal hidden emotions that are projected onto the test. In the Rorschach Inkblot Test a person is shown a series of ten black and white cards and asked to report the first thing that comes to mind. The participant then says what came to mind and may project some emotions onto the inkblot that were previous unmentioned. The person administering the test then records aspects of their reactions like gestures and tone of voice. In a thematic apperception test or TAT a person is shown an ambiguous scene and asked to create a story around it. The person can then reveal emotions that they did not previous mention in the story by stating how the characters feel and how the story ends. In a projective test a lot is up for interpretation based on the individual and how they are feeling at that time making the test lack both reliability and validity because of no grading scale being set in stone and results being inconsistent.
Explanation:
I just did this on edge. Brainliest?
Solution. To check whether the vectors are linearly independent, we must answer the following question: if a linear combination of the vectors is the zero vector, is it necessarily true that all the coefficients are zeros?
Suppose that
x 1 ⃗v 1 + x 2 ⃗v 2 + x 3 ( ⃗v 1 + ⃗v 2 + ⃗v 3 ) = ⃗0
(a linear combination of the vectors is the zero vector). Is it necessarily true that x1 =x2 =x3 =0?
We have
x1⃗v1 + x2⃗v2 + x3(⃗v1 + ⃗v2 + ⃗v3) = x1⃗v1 + x2⃗v2 + x3⃗v1 + x3⃗v2 + x3⃗v3
=(x1 + x3)⃗v1 + (x2 + x3)⃗v2 + x3⃗v3 = ⃗0.
Since ⃗v1, ⃗v2, and ⃗v3 are linearly independent, we must have the coeffi-
cients of the linear combination equal to 0, that is, we must have
x1 + x3 = 0 x2 + x3 = 0 ,
x3 = 0
from which it follows that we must have x1 = x2 = x3 = 0. Hence the
vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer. The vectors ⃗v1, ⃗v2, and ⃗v1 + ⃗v2 + ⃗v3 are linearly independent.
Answer: The answer is: f(x) = 2x^2 + 40x + 200
Explanation:
Given: x is the width of the Artwork
Let W be the Width of the Frame
Let L be the Length of the Frame
Width = x + 10
Length = Width * 2, so by substitution, Length = 2(x + 10)
Area = Width * Length
By substitution:
Area = (x + 10) * 2(x + 10)
f(x) = (x + 10) * (2x + 20)
f(x) = 2x^2 + 20x + 20x + 200
f(x) = 2x^2 + 40x + 200
To test this, if a picture 8" wide is put in this frame, the width would be 8+10 or 18 inches. The length would be twice the width, or 36 inches. The Area is 18 x 36 = 648.
Using the formula:
f(8) = (2 * 8^2) + (40 * 8) + 200
f(8) = (2 * 64) + 320 + 200
f(8) = 128 + 320 + 200
f(8) = 648
Middle English speakers adapted "socour," the predecessor of "succor<span>," from the Anglo-French sucors, which essentially had the same meaning as our modern word. "Sucors," in turn, derives from the Medieval Latin succursus, itself a derivative of the Latin verb succurrere, meaning "to run to the rescue or "to bring aid."</span>
