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Andre45 [30]
3 years ago
13

A certain star is 1.135 × 10^14 km away from Earth. If light travels at 9.4607 × 10^12 km per year, how long will it take for li

ght from the star to reach Earth?
Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

Approximately 11.99 years

Step-by-step explanation:

This is just a type of problem like finding how long it will take for you to get somewhere.  Like in finding how fast you need to go to go to a place that is 60 miles in one hour.  All you have to do is divide the distance of the star by the speed of light, and you get the amount of time it will take for the star's light to reach the Earth.

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Answer:

8(203-2xz)

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5 0
3 years ago
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What is the answer of:<br> z^2 - 4z^2
Novosadov [1.4K]
z^2 - 4 z^2

z - 4z

= - 3 z^2

hope this helps!.
4 0
3 years ago
PLEASE HELP I WILL MARK YOU BRAINLIEST<br><br> FIND THE AREA OF NUMBER 3 AND 4
scoray [572]

Answer:

3. 112.2 yd

4. 30m

Step-by-step explanation:

Number 3:

  1. L × W (length × width) = A
  2. 18.7 × 6 = 112.2 yd

Number 4:

  1. B × H (base × height) = A
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8 0
3 years ago
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If a polynomial has one root in the form a+√b , it has a second root in the form of a_√b
gulaghasi [49]
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.

The first factor is x - (a + √b).
The second factor is x - (a - √b).

The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
      = x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
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This is a quadratic polynomial, as expected.

If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
   = a +/- (1/2)*√(4b)
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3 years ago
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PLSSS HELP IF YOU TURLY KNOW THISS
solniwko [45]

Answer:

super simple its blueprints!

Step-by-step explanation:

7 0
2 years ago
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