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melamori03 [73]
3 years ago
6

Find a number such that three less than four times the number is two.

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0
Answer:
X=5/4 or 1.25

Solution:
Make algebraic equation to solve
4x-3=2
Solve
4x=2+3=5
X=5/4

Hope this helps. Please mark brainliest.
You might be interested in
Can anyone help me ?
taurus [48]

Answer:

_

66,6% = ⅔

_

33,3% = ⅓

85% = 17⁄20

80% = ⅘

75% = ¾

90% = 9⁄10

20% = ⅕

10% = ⅒

Step-by-step explanation:

To convert from a fraction to a percentage, divide both the denominator and numerator to get a decimal point, then move the decimal point twice to the right, then attach the percentage symbol:

⅒ = 0,1 = 10%

⤻⤻

⅕ = 0,2 = 20%

⤻⤻

9⁄10 = 0,9 = 90%

⤻⤻

¾ = 0,75 = 75%

⤻⤻

⅘ = 0,8 = 80%

⤻⤻

17⁄20 = 0,85 = 85%

⤻⤻

_ _

⅓ = 0,3 = 33,3%

⤻⤻

_ _

⅔ = 0,6 = 66,6

All those bars above those digits are what are known as bar notation, indicating that digits repeat.

I am joyous to assist you anytime.

6 0
3 years ago
Find area PLEASE PLEASE PLEASE
yan [13]

Answer: 39.22 yd^2 (as in yards squared)

Step-by-step explanation:

1. DO NOT FOCUS ON THE 6! JUST FOCUS ON THE BASE AND HEIGHT!

2. Area= b*h

3. Plus in your numbers. Area=3.7*10.6.

4. Multiply. Area=39.22 yds^2

4 0
3 years ago
A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
A rectangular prism has a length of 12in, a height of 5in, and a width of 8in. What is its volume, in cubic in?
cupoosta [38]

Answer: The volume is 480 in^3

Step-by-step explanation:

v= lwh

v= 12 * 5 * 8

v= 480 in^3

3 0
3 years ago
Read 2 more answers
melissa began atop a hill that was 1,350 feet high. she descended 120 feet, took a break and then descended 235 more feet. Which
Anna11 [10]
1500 is the answer I did this a while ago I think not sure
5 0
3 years ago
Read 2 more answers
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