Answer:
1:3
Step-by-step explanation:
You just have to divide them with the number that can divide the numbers
Answer:
There are 1% probability that the last person gets to sit in their assigned seat
Step-by-step explanation:
The probability that the last person gets to sit in their assigned seat, is the same that the probability that not one sit in this seat.
If we use the Combinatorics theory, we know that are 100! possibilities to order the first 99 passenger in the 100 seats.
LIke we one the probability that not one sit in one of the seats, we need the fraction from the total number of possible combinations, of combination that exclude the assigned seat of the last passenger. In other words the amount of combination of 99 passengers in 99 seats: 99!
Now this number of combination of the 99 passenger in the 99 sets, divide for the total number of combination in the 100 setas, is the probability that not one sit in the assigned seat of the last passenger.
P = 99!/100! = 99!/ (100 * 99!) = 1/100
There are 1% probability that the last person gets to sit in their assigned seat
I like to divide by 2 first, and 347 divided by 2 is 173.5, so obviously this won't turn out evenly. I then divide 173.5 by 2, and that would be 86.75, so there's your answer!
Hope this helps!
Answer:
Of the 1500 surveys sent out, 480 are returned, and of these, only 120 say they're satisfied with the president's job performance.
1.) The population is - all registered voters in this community.
Population represents the complete data set of a survey.
2.) The sample is - the 1500 randomly selected voters receiving the questionnaire.
A sample is the subset to the population.
3.) This is an example of - a survey with little bias since people understand whether they approve of the president's job performance.