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3 years ago

How to be good at maths if you cant keep up in class

2 answers:

5 0

You should definitely talk to your teacher about it, as well as check out Khan Academy online for detailed explanations and videos of the subject you're working on.

Eva8 [605]3 years ago

4 0

Tough question to answer in just a few words. For starters:

1) Read assigned portions of your textbook several times; outline what you are reading

2) Make a list of questions about material you don't understand; get help (here or from your teacher) with that material.

3) Read your textbook or other learning material BEFORE you attend class so that you'll have some familiarity with the vocabulary and subject matter. Going to class without having prepared in this way almost guarantees that you won't understand very much.

Plenty more. If you want further dialogue, ask some questions and I'll try to respond with something helpful.

You might be interested in

A bag contains 43 U.S. quarters and seven Canadian quarters. (The coins are identical in size.) If six quarters are randomly pic

Marrrta [24]

Answer:

0.616

Step-by-step explanation:

The number of Us quarters is 43 while the number of Canadian quarters is 7.

The number of quarters we are to pick is 6

Mathematically, the probability of getting at least one Canadian quarter = 1 - probability of getting no Canadian quarter

This means we have to calculate the probability of getting no Canadian quarter first.

The total number of possible outcomes is 50C6 = 15,890,700

If we are to get all to be US quarters, that means we are getting exactly 6 out of 43 = 43C6 = 6,096,454

Hence, probability of no Canadian quarters is 6,096,454/15,890,700 = 0.384

The probability of at least 1 Canadian quarters is thus 1-0.384 = 0.616

6 0

3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)<br><br> please check answer..

SCORPION-xisa [38]

Answer:

B. False, they could be vertical angles

Step-by-step explanation:

Supplementary just mean when two angles form 180° (a straight line).

So ∠F and ∠G must form a straight line, and ∠G and ∠H must form a a straight line.

I drew the image out below and as you can see, angle F and H forms a vertical angle. A vertical angles is when two lines cross, the opposite angles from each others are called vertical angles.

6 0

3 years ago

The endpoints of the segment AB are A(-2,4) and B(4,0). Find the endpoints of the image after the segment is reflected over the

serious [3.7K]

Answer:

A' ( 2, 4) and B' ( -4, 0)

Step-by-step explanation:

A ( -2, 4) and B( 4,0) reflected over the y-axis

A' ( 2, 4) and B' ( -4, 0)

the y-coordinate do not change and the x is opposite sign

(x,y) reflected over y-axis (-x, y)

3 0

3 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Len [333]

Answer: 3

Step-by-step explanation:

Given : Standard deviation : $\sigma=4.1\text{ seats}$

Margin of error : $E=\pm5\text{ seats}$

Significance level : $\alpha: 1-0.95=0.05$

By using the standard normal table of z ,

Critical value : $z_{\alpha/2}=1.96$

The formula we use to find the minimum sample size required :-

$n=(\dfrac{z_{\alpha/2}\ \sigma}{E})^2$

i.e. $n=(\dfrac{(1.96)(4.1)}{5})^2=2.58309184\approx3$

Hence, the number of lights should we select if we wish to estimate μ to within 5 seats and be 95 percent confident =3

6 0

3 years ago

15. For each of the following, write the probability as the intersection of two events. Then, indicate whether the two events ar

LuckyWell [14K]

Answer:

Step-by-step explanation:

a. The probability of selecting a 6 from the first draw and a 7 on the second draw when two balls are selected without replacement from a container with 10 balls numbered 1 to 10

Not independent because without replacement

Prob for both = $\frac{1}{10} \frac{1}{9} \\=\frac{1}{90}$

b. The probability of selecting a 6 on the first draw and a 7 on the second draw when two balls are selected with replacement from a container with 10 balls numbered 1 to 10

Here independent because with replacement makes probability independent.

Prob for both = P(A) *P(B) = $\frac{1}{10} *\frac{1}{10} \\=\frac{1}{100}$ d

c. The probability that two people selected at random in a shopping mall on a very busy Saturday both have a birthday in the month of June. Assume that all 365 birthdays are equally

likely, and ignore the possibility of a February 29 leap-year birthday.

Here independent because one person birthday will not affect the other person birthday

Prob for both = $(\frac{30}{365})^2\\ =\frac{25}{5329}$

d. The probability that two socks selected at random from a drawer containing 10 black socks and 6 white socks will both be black

Prob for I sock black = 10/16 and II sock black if first sock is black = 9/15

Hence not independent

Prob for both = $\frac{10C2}{16C2} \\=\frac{3}{8}$

5 0

4 years ago