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Allisa [31]
3 years ago
11

What's 1+1+2 (doing this to show my aunt)

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0

Answer:

4

Step-by-step explanation:


sasho [114]3 years ago
6 0

Answer:

The answer would be 4

Step-by-step explanation:

You can use PEMDAS and add left to right

1+1=2

2+2=4

Hope this helps!

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HELPPPP SOMEONE I need help
omeli [17]
Hey it’s me again lol.

Part a)

f(5) is inserting 5 into f(x) where x=5

(2•5) -1 = 9

Part B)

g(x-2) is inserting x-2 into g(x) where x =x-2

(x-2)^2 + x-2 + 1 = x^2 -4x +4 + x - 2 + 1

= x^2 -3x + 5


3 0
3 years ago
Read 2 more answers
Heyyy could someone please help me out?? Would appreciate it. Thanks in advance!!^^
vitfil [10]

Answer:

Below,...

Step-by-step explanation:

They are saying that if you add a odd number + a odd number than you'd get a even number,... odd + even = odd,... odd x even = even,... and so on,...

Hope it helps,... Chow!

5 0
3 years ago
A set of equations is given below:
Novay_Z [31]

These would have infinite solutions because this is a slope-intercept equation. Since you are provided with the y-intercept in both, you can put anything in for the slope and it will work.

Hope this helps!

8 0
3 years ago
4+2(x-2)=2(x-1)+2<br> which one<br> A. Infinitesolutions<br> B.x=0<br> C.x=3<br> D.x=-2<br> E.x=-3
fredd [130]

Answer:

B

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu
Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

Total                  2298                     170                  2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0
3 years ago
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