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lapo4ka [179]
3 years ago
15

How do i help people by answering there question

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0
What do you mean by this?
You might be interested in
How old will Susan be 5 years from now?
zhenek [66]

I think you forgot to mention Susan's current age if not:

x+5

x-4

6x

7 0
2 years ago
Charlie makes 9 dollars for each week of work. Write an equation to represent his total pay p after working h hours
sertanlavr [38]

Answer:

p = 9h

Step-by-step explanation:

:-)

3 0
2 years ago
There are 25 towns in a certain country, and every pair of them is connected by a train route. How many train routes are there?
7nadin3 [17]

Answer:

13

Step-by-step explanation:

a pair=2

so 25/each pair of towns

25/2=12+1=13

5 0
3 years ago
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard d
skelet666 [1.2K]

Answer:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(30,7.8)  

Where \mu=30 and \sigma=7.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.80   (a)

P(X   (b)

As we can see on the figure attached the z value that satisfy the condition with 0.20 of the area on the left and 0.80 of the area on the right it's z=-0.842

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=30 -0.842*7.8=23.432

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.  

8 0
3 years ago
What is 8.33333 as a fraction?
beks73 [17]
8 \frac{1}{3}

I only know this because I remember the common fractions, and 1/3 is .3333 repeating.
4 0
3 years ago
Read 2 more answers
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