The simplification of 25p^6q^9 / 45p^8q^4 using a positive exponent;
- Division is 5p^6 q^9 / 9p^8 q^4
- Elevated form is 5/9 p^-2 q^5
<h3>What are algebraic expressions?</h3>
Algebraic expressions are expressions made up of factors, variables, terms, coefficients and constants.
They are also comprised of arithmetic operations such as addition, subtraction, multiplication, division, etc
We also know that index forms are also know as standard forms.
They are mathematical expressions showing the power of exponent of a variable in terms of another variable.
Given the index algebraic forms;
25p^6q^9 / 45p^8q^4
Using the rule of indices, we take the negative exponent of the divisor and multiply through.
We have;
5p^6 q^9 × 9p^-8 q^-4
Add exponential values
5/9 p^6-8 q^9 -4
5/9 p^-2 q^5
Thus, the expression is simplified to 5/9 p^-2 q^5
Learn more about index forms here:
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The distance between (5,5) and (1,5) is 4 blocks
The formula to finding percentages is x% * y = c. So 7% of $4.90 is 0.343.
( 7% is 0.07)
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
Answer:
Where ??
Step-by-step explanation:
