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lapo4ka [179]
3 years ago
15

How do i help people by answering there question

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0
What do you mean by this?
You might be interested in
Solve for b: 16b = 12
Zina [86]

Answer:

b = 3/4

Step-by-step explanation:

Hi!!!

You want the value of B. To get that, we have to divide both sides by 16:

\frac{16}{16}b =\frac{12}{16}

\frac{12}{16} = \frac{3}{4}

Thus the answer to your question is $\boxed{b = \frac{3}{4} }.

<u>Check:</u>

3/4 * 16 = 3 * 4 = 12.

12 = 12

So we are correct!!!

5 0
3 years ago
In your top dresser drawer are 6 blue socks and 10 grey socks, unpaired and mixed up. One dark morning you pull two socks from t
pishuonlain [190]

Answer:

D) 0.500

Step-by-step explanation:

Blue Socks = 6

Grey socks = 10

Probabilities to find :

Since there are a total of 16 socks, the probability of both socks being blue is  

Probability(blue) = (\frac{6}{16} ) \frac{5}{15} =\frac{30}{240} =\frac{1}{8}

The probability of both being grey is  

Probability(grey)  =(\frac{10}{16} ) \frac{9}{15} =\frac{90}{240} =\frac{3}{8}

(Note: After 1 sock is picked , next sock drawn would have a different probability as 1 sock is already picked so it would be 1 minus the total socks available of that color)

The probability two socks match:

Probability(blue) + Probability(grey) = \frac{1}{8} + \frac{3}{8}  = \frac{4}{8}  =\frac{1}{2} = 0.500

5 0
3 years ago
Can you help me with this please..
jonny [76]

Answer:

0.5

Step-by-step explanation:

Ok, so it's asking for what (1/(x-1) - 2/(x^2-1)) approaches as x approaches 1. Before we deal with the limit, let's simplify the inside.

We want to combine the two fractions into one fraction. Therefore, we need a common denominator.

1/(x-1) is equal to (x+1)/((x+1)(x-1) is equal to (x+1)/(x^2-1).

the inside expression is therefore (x+1)/(x^2-1) - 2/(x^2-1)

which simplifies to (x-1)/(x^2-1).

and that simplifies further to 1/(x+1).

Now this is a continuous function when x = 1, so to find the limit as x approaches 1 of this function, we can by definition just plug 1 in.

limx->1 (1/(x+1)) = 1/2.

The reason why we didn't just plug 1 in at the beginning is because the function wasn't continuous when x was 1.

8 0
3 years ago
larry earned $11 walking his neighbors' dogs on saturday. he earned some extra money on sunday doing the same thing. write an ex
jok3333 [9.3K]
This is easy. He first earned $11 on Saturday and then on Sunday he earned some money. We don't know how much he earned, we just know he earned some money. Let's put the expression together. A good place to start would be the $11. Let's add eleven to the expression. And because he earned some more money, it's going to be addition. So currently, the expression stands at $11 + 
And because we don't know how much money he made on Sunday, x will be the variable for how much he earned. So the expression will be 

11 + x

6 0
3 years ago
Find the product of the following polynomials:
qaws [65]

Answer:

A)  -84x^3 - 8x

B)  -91x^4 + 143x^2 - 65x

C)  12b^2 - 7b - 10.

D)  16x^2 - 72x + 81

Step-by-step explanation:

A) -4x(21x^2-3x+2)  

B) -13x(7x^3-11x+5)

C) (3b+2)(4b-5)

D) (4x-9)^2

In A) -4x(21x^2-3x+2)  we are multiplying the binomial (21x^2-3x+2)  by the monomial -4x; there are two multiplications involved:  

-4x(21x^2) = -84x^3

and

-4x(-3x+2) = +12x^2 - 8x.

Hence A) -4x(21x^2-3x+2)   = -84x^3 - 8x

B)  The work done to find the product in B) is similar:  Multiply each term in 7x^3-11x+5 by -13x:

The end result is -91x^4 + 143x^2 - 65x

C) Here we are multiplying together two binomials; we use the FOIL method:  Multiply together the First terms, then the Outer terms, then the Inner terms, and finally the Last terms.  This results in:

(3b+2)(4b-5)  = 12b^2 -15b + 8b -10, or, after simplification, 12b^2 - 7b - 10.

In D) we are squaring a binomial.  The formula for this is:

(a - b)^2 = a^2 - 2ab + b^2.  Here,

(4x - 9)^2 = 16x^2 - 2(36x) + 81, or 16x^2 - 72x + 81

5 0
3 years ago
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