Question

What's 3x-5y=9;x=-1,0,1?

Answer 1

One easy way is first solve for y
3x-5y=9
minus 3x both sides
-5y=-3x+9
divide both sides by -5
y=$\frac{3x-9}{5}$

so

if x=-1
y=$\frac{3(-1)-9}{5}$
y=$\frac{-3-9}{5}$
y=$\frac{-12}{5}$

if x=0
y=$\frac{3(0)-9}{5}$
y=$\frac{0-9}{5}$
y=$\frac{-9}{5}$

if x=1
y=$\frac{3(1)-9}{5}$
y=$\frac{3-9}{5}$
y=$\frac{-6}{5}$