Answer:
25
Step-by-step explanation:
So, first lets define our variables:
let x = the number of dimes
let y = the number of nickels
so our first equation would be x+y = 16
Since dimes are 10 cents and nickels are 5 cents the next equation would be as follows:
.10x+.05y = 1.35
now change the first equation so y = -x+16
now substitute:
.10x+.05(-x+16) = 1.35
then multiply so you get .10x+-.05x+0.8=1.35
combine like terms and you get .05x+0.8 = 1.35
then subtract 0.8 from both sides and you get .05x = 0.55 then subtract
and you get x = 11 then substitute 11 for where x should be and you should get y = 5
So, you have 11 dimes and 5 nickels
i think the person below me is correct and the answer is 12
Answer:
Value of the test statistic, 
Step-by-step explanation:
Null hypothesis, 
Alternative hypothesis, 
Sample mean, 
Sample size, n = 110
Standard deviation, 
Significance level, 
The value of the test statistics is given by the formula:

Answer:
a)
Step-by-step explanation:
hello,
because of the end behaviour the constant in
should be positive so we have a) or d)
f(0)=-3 in both cases
for A) f(x)=

so f(x)=0 for 
so the correct answer is A)
hope this helps