Point? I'm pretty sure or the origin point
Answer:
a. At t = 5 s

b. At t = 10 s

c. At t = 20 s

Step-by-step explanation:
We know that the velocity function is given by

Acceleration is the rate of change of velocity so we take the derivative of the velocity function with respect to time.



a. At t = 5 s

b. At t = 10 s

c. At t = 20 s

Answer:
i wish i could help u!!!!!!
Step-by-step explanation:
uuuhhhhh i hate that i kinda suck at math
anyway, i'll give this my best shot
The midsegment of a triangle is a line segment that connects the midpoints of two sides ofrigidity to structures. In the support for the image shown shown, the crossbar GJK is a midsegment of GFK
You can use a compass and straightedge to construct the midsegments of a triangle.
Hope this helps! It's the best i can do!
Answer:

Step-by-step explanation:
1) Given that the formula for the Newton Method is:

2) The Function and its 1st derivative

3) Let's work with the first approximation. Plugging in in the function:

4) To approximate the other root x

A 5 cm×11 cm\greenD{5\,\text{cm} \times 11\,\text{cm}}5cm×11cmstart color #1fab54, 5, start text, c, m, end text, times, 11, sta
sashaice [31]
Answer:
42.5 square.cm
Step-by-step explanation:
Find the diagram attached
Area of the shaded portion = area of square - area of circle
Area of square = L²
Area of square = 11 × 11
Area of square = 121 square centimetres
Area of circle = pir²
r is the radius of the circle = 5cm
Area of the circle = 3.14×5²
Area of the circle = 3.14×25
Area of the circle = 78.5 square. cm
Area of the shaded region = 121 - 78.5
Area of the shaded region = 42.5 square.cm