Question

A cylindrial hole is cut through the cylinder below.

Answer 1

Answer:

V=1884 Cubic mm

Step-by-step explanation:

We know that the volume of the Sphere is given by the formula

$V= \pi r^2h$

Where r is the radius and h is the height of the cylinder

We are asked to determine the radius of the hollow cylinder , which will be the difference of the solid cylinder and the cylinder being carved out.

$V=V_1-V_2$

$V=\pi r_1^2 \times h-\pi r_2^2 \times h$

$V=\pi \times h \times (r_1^2-r_2^2)$

Where

$V_1$ is the the volume of solid cylinder with radius $r_1$ and height h

$V_2$ is the volume of the cylinder being carved out with radius $r_2$ and height h

where

$r_1 = 7$ mm ( Half of the bigger diameter )

$r_2 = 5$ mm ( Half of the inner diameter )

$h=25$ mm

Putting these values in the formula for V we get

$V=\pi \times 25\times (7^2-5^2)$

$V=3.14 \times 25 \times(49-25)$

$V=3.14 \times 25 \times 24$

$V= 1884$