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Rainbow [258]
3 years ago
13

BRAINLIEST ASAP! PLEASE HELP ME :) thanks!

Mathematics
2 answers:
Evgen [1.6K]3 years ago
6 0

Answer:

SAS

Step-by-step explanation:

It is SAS similarity because the two sides are proportional, and the angle is the same. SAS works because it can also be proved for congruence.

Mumz [18]3 years ago
3 0

The answer is [ yes; ΔABC ~ ΔRTS by SAS similarity ]

SAS similarity means that both triangles have corresponding sides that have similar ratios and corresponding angles that are congruent.

In both triangles, ΔABC and ΔRTS have the same degree which is 42.

In both triangles, they have a scale factor of 3 which means that they both have identical ratios.

This proves our answer.

Best of Luck!

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Identify the diameter of the circular base created by folding the figure into a right cone. HELP ASAP PLEASE!!
Akimi4 [234]

let's notice something, we have a circle with a radius of 12 and one 90° sector is cut off, so only three 90° sectors of the circle are left shaded, so namely the cone will be using 3/4 of that circle.

think of it as, this shaded area is some piece of paper, and you need to pull it upwards and have the cutoff edges meet, and when that happens, you'll end up with a cone-shaped paper cup, and pour in some punch.

now, once we have pulled up the center of the circle to make our paper cup, there will be a circular base, its diameter not going to be 24, it'll be less, but whatever that base is, we know that is going to have the same circumference as those in the shaded area.  Well, what is the circumference of that shaded area?

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies C=2\pi 12\implies C=24\pi \implies \stackrel{\textit{three quarters of it}}{24\pi \cdot \cfrac{3}{4}} \\\\\\ 6\pi \cdot 3\implies 18\pi

well then, the circumference of that circle at the bottom will be 18π, so, what is the diameter of a circle with a circumferenc of 18π?

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=18\pi \end{cases}\implies 18\pi =2\pi r\implies \cfrac{18\pi }{2\pi }=r\implies 9=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{diameter is twice the radius}}{d=18}~\hfill

3 0
3 years ago
4,6,9,...<br> Find the 8th term.<br> Find the 8th term.
krek1111 [17]

Answer:

4, 6, 9, 12, 15, 18, 21, <u><em>24.</em></u>

Step-by-step explanation:

The 8th term is 24.

just +2 (add 2) every time.

3 0
3 years ago
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