Answer:
232.5
Step-by-step explanation:
If you take 15.50 and multiply it by 15 you get 232.5 if its wrong my apologies
Answer:
x=2 and y=−6
sorry this is pretty long, I did not know if you needed the steps or not
Step-by-step explanation:
−2y−10=x;−10x−y=−14
Solve−2y−10=x for x
−2y−10=x
−2y−10+−x=x+−x
−x−2y−10=0
−x−2y−10+2y=0+2y
−x−10=2y
−x−10+10=2y+10
−x=2y+10
-x/-1=2y+10/-1
x=−2y−10
Substitute−2y−10 for x in−10x−y=−14
−10x−y=−14
−10(−2y−10)−y=−14
19y+100=−14
19y+100+−100=−14+−100
19y=−114
19y/19=-114/19
y=-6
Substitute−6 for y in x=−2y−10
x=−2y−10
x=(−2)(−6)−10
x= 2
x=2 and y=−6
0.600 = six thousandths written out
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer:
x>-2 and x<5
-2 <x<5
Step-by-step explanation:
We have open circles at -2 and 5 and are between the two numbers so we have and AND statement. It can be written either
x>-2 and x<5
or
-2 <x<5
