Given:
The figure of a rhombus QRST.
To find:
A. The value of x.
B. The measure of angle RQP.
Solution:
A. We need to find the value of x.
We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.
[Right angle]
Divide both sides by 5.
Therefore, the value of x is 15.
B. We need to find the measure of angle RQP.
From the given figure, it is clear that
Putting , we get
Therefore, the measure of angle RQP is 33 degrees.
We can say that x is the largest number.
So the sum is x + (x - 1) + (x - 2) + (x - 3) + (x - 4) = -5
Now solve for x:
x + x + x + x + x - 1 - 2 - 3 - 4 = -5
5x - 10 = -5
5x = 5
x = 1
So the largest number is 1.
Check: 1 + 0 + -1 + -2 + -3 = -2 + -3 = -5 so 1 is correct.
Slope intercept is y=mx+b
m=slope
slope if found by
m=(y1-y2)/(x1-x2)
(x,y)
(-1,-2) and
(1,2)
x1=-1
y1=-2
x2=1
y2=2
m=(-1-1)/(-2-2)
m=-2/-4
m=1/2
y=1/2x+b
solve fo by subsituting one x value
(1,2)
x=1
y=2
2=1/2(1)+b
2=1/2+b
subtract 1/2
3/2=b
equation is
y=1/2x+3/2
62=14 + 2x
62-14=2x
48=2x
48/2=x
24 answer: 24
hope this helped
