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pashok25 [27]
3 years ago
9

What’s the correct answer for this?

Mathematics
1 answer:
DiKsa [7]3 years ago
6 0
48 degrees

The triangles are congruent, so if angle B is between side lengths 6 and 6.2, it’s going to be the same for the other triangle
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What is the size of the sample space for flipping 7 coins? Write your answer as a single integer.
Elenna [48]
I think the answer is 6
4 0
2 years ago
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Find the circumference of a circle with an area of 676pi
saveliy_v [14]

Answer:

The circumference of the circle is 52π

Step-by-step explanation:

To solve this exercise we first have to calculate the radius of the circle, for this we will use the formula of area of ​​a circle and we will clear the radius

a = area = 676π

r = radius

a = π * r²

we clear r

r = √(a/π)

now we replace the known values

r =  √(676π/π)

r = √(676)

r = 26

now we use the formula to calculate the circumference of a circle

c = π * 2r

c = π * 2 *  26

c = 52π

The circumference of the circle is 52π

6 0
2 years ago
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Which of the following equations represents the perpendicular bisector of WX graphed below?
kotykmax [81]
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2} )=  (\frac{-5+5}{2},  \frac{2+(-4)}{2} )=(0, -1).

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is \displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}.

Thus, the slope n of the perpendicular line is \displaystyle{  \frac{5}{3}.

The equation of the line with slope \displaystyle{ n= \frac{5}{3} containing the point M(0, -1) is given by:

\displaystyle{ y-(-1)=\frac{5}{3}(x-0)

\displaystyle{ y+1= \frac{5}{3}x

\displaystyle{ 3y+3=5x

\displaystyle{ 5x-3y-3=0

Answer: 5x-3y-3=0
8 0
3 years ago
Every hour of training raises the salary
timurjin [86]
(10,1250),(20,1400)
slope = (1400 - 1250) / (20 - 10) = 150/10 = 15

so every hr of training raises the salary by $ 15
7 0
3 years ago
3. (6 Points). Solve the initial value problem y'-y.cosx=0, y(pi/2)=2e
Stells [14]

Answer:

y=2e^{sin(x)}

Step-by-step explanation:

Given equation can be  re written as

\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating  \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c............(i)

Now it is given that y(π/2) = 2e

Applying value in (i) we get

ln(2e) = sin(π/2) + c

=> ln(2) + ln(e) = 1+c

=> ln(2) + 1 = 1 + c

=> c = ln(2)

Thus equation (i) becomes

ln(y) = sin(x) + ln(2)

ln(y) - ln(2) = sin(x)

ln(y/2) = sin(x)

y= 2e^{sinx}

7 0
3 years ago
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