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pashok25 [27]
3 years ago
9

What’s the correct answer for this?

Mathematics
1 answer:
DiKsa [7]3 years ago
6 0
48 degrees

The triangles are congruent, so if angle B is between side lengths 6 and 6.2, it’s going to be the same for the other triangle
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It is known that there only is 1% chance of getting a disease. a test is being devised to detect the disease. the probability th
Cerrena [4.2K]
Suppose D is the event that a given patient has the disease, and P is the event of a positive test result.

We're given that

\mathbb P(D)=0.01
\mathbb P(P\mid D)=0.98
\mathbb P(P^C\mid D^C)=0.95

where A^C denotes the complement of an event A.

a. We want to find \mathbb P(P^C). By the law of total probability, we have

\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)

That is, in order for P^C to occur, it must be the case that either D also occurs, or D^C does. Then from the definition of conditional probability we expand this as

\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)

so we get

\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407

b. We want to find \mathbb P(D\mid P). Now, we can use Bayes' rule, but if you're like me and you find the formula a bit harder to remember, we can easily derive it.

By the definition of conditional probability,

\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}

We have the probabilities of P/P^C occurring given that D/D^C occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of P being conditioned on D:

\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)

Meanwhile, the law of total probability lets us rewrite the denominator as

\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)

or in terms of conditional probabilities,

\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)

so that

\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}

which is exactly what Bayes' rule states. So we get

\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653
6 0
3 years ago
Match the pre-image, and its clockwise rotation, with the coordinates of its image. 1. (5, 2); 90° (-2, -5) 2. (5, 2); 180° (2,
lawyer [7]
1. (2,-5)
2. (-5,-2)
3. (-2,5)
4. (2,5)
5. (5,-2)
6. (-2,-5)
7. (5,2)
8. (-5,2)

Each 90° clockwise turn takes a point (x,y) and transforms it to (y,-x). For a 180° turn you would do this process twice in a row; for a 270° turn, three times in a row.
5 0
4 years ago
During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th
ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given :  J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901  (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

P(X=x)^nC_xp^x(1-p)^{n-x}

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901     (from (1))

The probability that he makes at least 13 of them will be :-

P(x\geq13)=P(x=13)+P(x=14)

=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898

∴ The required probability = 0.5898

5 0
3 years ago
PLEASE HELP BEST ANSWER GETS BRAINLIEST AND 50 POINTS
Simora [160]

Answer:

The relative frequency of males choosing a sports utility vehicle is 0.35

The relative frequency of females choosing a sport utility vehicle is 0.75

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The relative frequency of females choosing a sports car is 0.25

The relative frequency of males or females choosing a sport utility vehicle is 0.65

The relative frequency of males or females choosing a sports car is 0.35

Step-by-step explanation:

5 0
3 years ago
⚠️NEED HELP ASPA⚠️<br> Determine whether each pair of triangles is similar. Justify your answer.
bekas [8.4K]
So the answer is A. The way to check if triangles are similar is find the ratio and make sure they are equal.
For example if you divide 42 by 27 you get 1.55
And if you do that to all the sides you also get 1.55 so therefore they are similar
7 0
3 years ago
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