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ValentinkaMS [17]
3 years ago
8

You have three 1 dollar bills and 2 10 dollar bills in your wallet. you select a bill at random

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

you are more likely to get a 10 dollar bill

Step-by-step explanation:

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1. It takes the Earth 24 h to complete a full rotation. It takes the sun approximately 25 days, 9 h, and 7 min to complete a ful
brilliants [131]

Note that there are 24 hours in 1 day, and 60 minutes in 1 hour

First, multiply 25 with 24

25 x 24 = 600

Next, add 600 with 9 hours

600 + 9 = 690

Note that there are 60 minutes in 1 hour. Divide 7 minutes with 60

7/60 = ~0.12 (rounded)

~690.12 hours is your answer

hope this helps

6 0
3 years ago
Read 2 more answers
Does anyone live in Alabama
Crank

Answer: No. Do you?

Step-by-step explanation:

4 0
3 years ago
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if a snowball rolls down a hill and its surface area increaces at a rate of 18cm^2/min, find the rate at which the radius increa
sp2606 [1]

Answer: dr/dt = 9/(24pi)  cm per minute

9/(24pi) is approximately equal to 0.119366

=============================================

Work Shown:

Given info

dS/dt = 18 cm^2/min is the rate of change of the surface area

r = 6 cm is the radius, from the fact that the diameter is 12 cm

--------

Use the surface area equation given, apply the derivative, plug in the given values and then isolate dr/dt which represents the rate of change for the radius

S = 4*pi*r^2

dS/dt = 2*4*pi*r*dr/dt

dS/dt = 8*pi*r*dr/dt

18 = 8*pi*6*dr/dt

18 = 48*pi*dr/dt

48pi*dr/dt = 18

dr/dt = 18/(48pi)

dr/dt = (9*2)/(24*2pi)

dr/dt = 9/(24pi)

The units are cm per minute, which can be written as cm/min.

3 0
3 years ago
There are 6 apples in a bowl containing 8 pieces of fruit what is the ratio of apples to the total number of fruit. If two piece
snow_lady [41]
So I think it’s 6:2 bc 6 apples and two oranges make 8 so the 8 pieces of fruit are the apples and oranges meaning that it probably put that to throw you off
4 0
2 years ago
The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi
fenix001 [56]

Answer:

Step-by-step explanation:

Given that

\alpha =2.5 ,\beta =220

The weibull distribution with parameters \alpha \ \ and \ \ \beta

where \alpha =0 \ \ , \beta =0

F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha  &x\geq 0\\0&x

Then,

F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x

A) The probability that a specimen's lifetime is at most 250 is

P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564

The probability that the specimen's life time is more than 300 is

P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}

=e^-^{(300/220)^{2.7}

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

P(100

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

P(X>x)=0.50\\\\1-P(X

x = 192.07

7 0
3 years ago
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