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bazaltina [42]
3 years ago
9

D. Find the value of x.1.120​

Mathematics
1 answer:
likoan [24]3 years ago
4 0
X=60 because 120/2=x
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Rita is spending more time at home to study and practice math. Her efforts are finally paying off. On her first assessment she s
Kipish [7]

Answer:

7th

Step-by-step explanation:

63 - 58 = 5

68-63 = 5

She is adding 5 points each time

a1 = 58

d = 5

a2 = 63

a3 = 68

a4 = 58+5 = 73

a5 = 73+5 = 78

a6 = 78+5 = 83

a7 = 83+5 = 88

This is the first assessment greater then 85, so the 7th assessment

4 0
3 years ago
I'm in algebra 1 please help i'm so lost
9966 [12]

<span><span>3+<span>xx</span></span>=19 </span>

<span /><span><span><span>x2</span>+3</span>=19 </span>

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<span><span>−3</span></span><span><span><span><span><span>x2</span>=16</span></span></span></span>

<span><span><span><span /><span>x=<span>±<span>√16</span></span></span></span></span></span>

<span><span><span><span><span><span /></span></span></span></span></span>x = <span><span><span><span>4‌</span>‌ or </span>‌</span>‌x </span>= <span>−<span>4</span></span>

6 0
3 years ago
Need help with this one.
ella [17]

Answer:

The answer should be 55

Step-by-step explanation:

All triangles must = 180

70+55+55 = 180

6 0
3 years ago
Read 2 more answers
Someone please help me! Studying for finals and don’t understand how to complete problems like this! Thank you!
Drupady [299]

Answer:

(d). \frac{152}{377}

Step-by-step explanation:

sin² β + cos² β = 1

cos (α + β) = cos α cos β - sin α sin β

cos α = √(1 - \frac{400}{841} ) = 21 / 29

cos β = 12 / 13

sin β = √(1 - \frac{144}{169} ) = 5 / 13

sin α = 20 / 29

cos (α + β) = \frac{21}{29} × \frac{12}{13} - \frac{20}{29} × \frac{5}{13} = \frac{152}{377}

6 0
3 years ago
Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"
dsp73
For any scalars c_1,c_2, we have

c_1\mathbf v\times c_2\mathbf w=c_1c_2\mathbf v\times\mathbf w

So

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\mathbf v\times\mathbf w

We have

\mathbf v\times\mathbf w=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\-2&12&-3\\-7&4&-6\end{vmatrix}
=\begin{vmatrix}12&-3\\4&-6\end{vmatrix}\mathbf i-\begin{vmatrix}-2&-3\\-7&-6\end{vmatrix}\mathbf j+\begin{vmatrix}-2&12\\-7&4\end{vmatrix}\mathbf k
=-60\,\mathbf i-(-9)\,\mathbf j+76\,\mathbf k
=\begin{bmatrix}-60\\9\\76\end{bmatrix}

which makes

\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}
4 0
3 years ago
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