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san4es73 [151]
3 years ago
10

Check the month and dollar value that when placed together would form a correct ordered pair. In April, Bob's Booksmart had a pr

ofit of $2,000. In May the profit was $3,000 dollars. In June the profit was $5,000.
A.April,


B. May,


C.June,


D.July


E.$1,000,


F. $2,000,


G.$4,000,


H.$6,000
Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

I also believe it is $6,000

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Answer:

x=9

Step-by-step explanation:

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90 points please help!!!!!!!!
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To model this situation, we are going to use the exponential function: f(t)=P(1+ \frac{r}{n} )^{nt}
where
P is the initial number of cars
r is the growing rate in decimal form 
n is number of tames the growing rate is increasing per year
t is the time in years

To convert the growing rate to decimal form, we are going to divide the rate by 100%
r= \frac{12}{100}
r=0.12
Since the growing rate is increasing quarterly, n=4. We also know that the initial number of cars is 920, so P=920. Lets replace all those values in our function:
f(t)=920(1+ \frac{0.12}{4} )^{4t}
f(t)=920(1+0.03)^{4t}
f(t)=900(1.03)^{4t}

We can conclude that:
Rate ---------> The quarterly rate of growth is 0.03 or 3%
Exponent --------> The compound periods multiplied by the number of years                                 is 4t
Coefficient--------> The initial number of cars serviced is 920
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Diagram 1 shows a composite solid consisting of a cuboid and a right pyramid.
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Line because a line is not 3-D
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A box has two balls, one white and one red. We select one ball, put it back in the box, and select a second ball (sampling with
AleksAgata [21]

Answer:

P (T) = 1/4

P ( T | F )    = 1/2  = P(F)

The events are not independent.

Step-by-step explanation:

Let F the event of picking the white ball first

P (F)= 1/2   ( picking the white ball first)

Let T be the event of getting the white ball twice,

P (T) = P( getting white ball) * P( getting white ball)

          =( 1/2)*(1/2)

           = 1/4

Here P(T∩F) = P(T) because the probability of getting the white balls is the same as probability of getting the white ball first  both the times.

P ( T | F ) = P (T∩F)/ P(F)

                = (1/4)/ (1/2)

                  = (1/2)

                    = 1/2  = P(F)

For the events to be independent the conditional probability P ( T | F )  must be equal to P(T).

Hence the events are not independent.

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