Define a lambda function that accepts one argument (a list of strings) and returns a list of only the words that start with an '

Question

3 years ago

9

Define a lambda function that accepts one argument (a list of strings) and returns a list of only the words that start with an '

e'. Assign the variable Lambda to your lambda function. Note: you must use a lambda function. For example: Lambda(["meaning", "cart", "engine", "egg"]) should be ["engine", "egg"]. eLambda(["mart", "nibble"]) should be []

Computers and Technology

1 answer:

Grace [21] · Answer 1 · 2022-05-09T07:52:02+03:00

Answer:

def Lambda(strList):
return list(filter(lambda s: (s.startswith("e")), strList))
print(Lambda(["meaning", "cart", "engine", "egg"]))

Explanation:

The solution code is written in Python 3.

Lambda function is an anonymous function. It is a function without any name and it is started with keyword lambda. To write a lambda function to filter the string started with an 'e', we can write a lambda expression, s.startswith("e") that work on one input strList. If any word from strList started with letter "e", the word will be added into a list generated by filter function. At the end, the Lambda function will return the list of strings as output.

When we test the Lambda function using the sample string list (Line 4), we shall get ['engine', 'egg'] printed to terminal.